Some Questions of Approximation of Almost Periodic Functions with Bounded Spectrum
E. A. BREDIKHINA
Submitted 1960-01-01 | SovietRxiv: ru-196001.67944 | Translated from Russian

Abstract Generated abstract

This paper studies approximation of uniformly almost-periodic functions whose Fourier exponents accumulate at zero, focusing on estimates obtained by deleting or approximating the low-frequency part of the spectrum. It introduces approximation quantities tied to a spectral cutoff and proves bounds in terms of averaged integrals of the function, with sharper estimates for classes admitting successive almost-periodic primitives. These estimates are then used to bound deviations of Fourier partial sums and to derive sufficient conditions for uniform convergence of the Fourier series, including refinements of known criteria and results under lacunarity-type assumptions on the exponent sequence.

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MATHEMATICS

E. A. BREDIKHINA

SOME QUESTIONS ON THE APPROXIMATION OF ALMOST-PERIODIC FUNCTIONS WITH BOUNDED SPECTRUM

(Presented by Academician V. I. Smirnov on 4 XII 1959)

  1. We denote by \(S\) the class of almost-periodic functions \(f(x)\) (here and below uniformly almost-periodic functions are meant) and introduce the corresponding Fourier series:
    \[ f(x)\sim \sum_{k=-\infty}^{\infty} A_k e^{i\Lambda_k x} \]
    \[ (\Lambda_0=0;\quad \Lambda_{k+1}<\Lambda_k\ \text{for } k>0;\quad \lim_{k\to\infty}\Lambda_k=0;\quad \Lambda_{-k}=-\Lambda_k;\quad A_0=0;\quad (1) \]
    \[ |A_k|+|A_{-k}|>0\quad \text{for } k\ne 0). \]

We denote by \(L=L(f)\) the sequence \(\{\Lambda_k\}\) \((k=1,2,\ldots)\).

We shall say that an almost-periodic function \(f(x)\) belongs to the class \(S_n\) \((n=1,2,\ldots)\), if there exist functions \(f_0(x), f_1(x),\ldots,f_n(x)\) possessing the following properties: \(f_0(x)=f(x)\), \(f'_{m+1}(x)=f_m(x)\) \((m=0,1,\ldots,n-1)\), \(f_m(x)\in S\) \((m=0,1,\ldots,n)\). The inclusions
\[ S\subset S_1\subset S_2\subset\cdots \]
are obvious.

Put
\[ R_\varepsilon(f)=\operatorname{Sup}_{x}\left|f(x)-\sum_{|\Lambda_k|>\varepsilon} A_k e^{i\Lambda_k x}\right|, \]
\[ e_\varepsilon(f)=\operatorname{Inf}_{c_k}\left\{\operatorname{Sup}_{x}\left|f(x)-\sum_{|\Lambda_k|>\varepsilon} c_k e^{i\Lambda_k x}\right|\right\},\qquad E_\varepsilon(f)=\operatorname{Inf}_{F(x)\in Q_\varepsilon}\left\{\operatorname{Sup}_{x}|f(x)-F(x)|\right\}, \]
where \(Q_\varepsilon\) is the class of almost-periodic functions whose Fourier exponents \(\{\lambda_k\}\) satisfy the condition \(|\lambda_k|>\varepsilon\).

Let
\[ \Omega_f(N)= \begin{cases} \displaystyle \operatorname{Sup}_{|T|\ge N}\left\{\operatorname{Sup}_{x}\left|\frac1T\int_0^T f(x+t)\,dt\right|\right\}, & N>0,\\[1.2em] \displaystyle \operatorname{Sup}|f(x)|, & N=0; \end{cases} \]
\(\Omega_f(N)\) is a continuous, bounded, nonincreasing function. For every function \(f(x)\in S\),
\[ \lim_{N\to\infty}\Omega_f(N)=0. \]

  1. Theorem 1. If \(f(x)\in S\), then
    \[ e_\varepsilon(f)\le C_0\Omega_f\left(\frac1\varepsilon\right), \tag{2} \]
    where \(C_0\) is an absolute constant.

Proof. Put
\[ \varphi_\varepsilon(t)= \begin{cases} 1, & 0\le |t|\le \varepsilon,\\[0.4em] \displaystyle 1-6\left(1-\frac{|t|}{\varepsilon}\right)^2-6\left(1-\frac{|t|}{\varepsilon}\right)^3, & \varepsilon<|t|<\dfrac{3\varepsilon}{2},\\[0.8em] \displaystyle 2\left(2-\frac{|t|}{\varepsilon}\right)^3, & \dfrac{3\varepsilon}{2}<|t|\le 2\varepsilon,\\[0.8em] 0, & |t|>2\varepsilon; \end{cases} \]

then

\[ \Psi_\varepsilon(u)=\frac{1}{2\pi}\int_{-\infty}^{\infty}\varphi_\varepsilon(t)e^{-iut}\,dt = \frac{12}{\pi}\, \frac{ 8\sin^3\frac{\varepsilon u}{4}\sin\frac{5\varepsilon u}{4} +\sin\varepsilon u\left(2\sin\frac{\varepsilon u}{2}-\varepsilon u\right) }{ \varepsilon^3u^4 }, \]

\[ \rho_\varepsilon(f,x)=\int_{-\infty}^{\infty} f(x+u)\Psi_\varepsilon(u)\,du \sim \sum_{|\Lambda_k|\leq\varepsilon} A_k e^{i\Lambda_k x} + \sum_{\varepsilon<|\Lambda_k|\leq 2\varepsilon} \varphi_\varepsilon(\Lambda_k)A_k e^{i\Lambda_k x}. \]

It is easy to see that

\[ e_\varepsilon(f)\leq \operatorname{Sup}_{x}|\rho_\varepsilon(f,x)|. \tag{3} \]

Integrating by parts, we obtain

\[ \rho_\varepsilon(f,x)=-\int_{-\infty}^{\infty} F(u,x)\Psi'_\varepsilon(u)\,du, \qquad \text{where } F(u,x)=\int_0^u f(x+t)\,dt. \]

For any real \(c\) the inequality holds

\[ \operatorname{Sup}_{x}|F(cu,x)|\leq (2+|c|)|u|\,\Omega_f(|u|), \]

therefore

\[ \rho_\varepsilon(f,x)\leq C_0\Omega_f\left(\frac{1}{\varepsilon}\right), \tag{4} \]

where

\[ C_0=\frac{12}{\pi}\int_{-\infty}^{\infty}(2+|v|) \left| \left[ \frac{ 8\sin^3\frac{v}{4}\sin\frac{5v}{4} +\sin v\left(2\sin\frac{v}{2}-v\right) }{ v^4 } \right]' \right|\,dv. \]

From (3) and (4) follows the estimate (2) to be proved.

Corollary. If there exist constants \(A\) and \(\alpha\) \((0<\alpha\leq 1)\) such that

\[ \left|\int_0^u f(x+t)\,dt\right|<A|u|^{1-\alpha}, \tag{5} \]

then

\[ e_\varepsilon(f)\leq \operatorname{const}\cdot \varepsilon^\alpha. \tag{6} \]

Proof. In view of (5), \(\Omega_f\left(\frac{1}{\varepsilon}\right)\leq A\varepsilon^\alpha\). Note that the estimate (6) follows from the results of the paper \((^1)\) (see also \((^2)\)).

Theorem 2. If \(f(x)\in S_n\), then

\[ e_\varepsilon(f)\leq C_n\varepsilon^n\Omega_{f_n}\left(\frac{1}{\varepsilon}\right), \tag{7} \]

where \(C_n\) is a constant depending only on \(n\).

The proof of the theorem is carried out by the induction method and is based on the following lemma.

Lemma. If \(f(x)\in S_1\), then

\[ e_\varepsilon(f)\leq C\varepsilon \operatorname{Sup}|f_1(x)|, \]

where

\[ C=\frac{12}{\pi}\int_{-\infty}^{\infty} \left| \left[ \frac{ 8\sin^3\frac{v}{4}\sin\frac{5v}{4} +\sin v\left(2\sin\frac{v}{2}-v\right) }{ v^4 } \right]' \right|\,dv. \]

In the estimate (7), \(C_n=C_0C^n\).

In view of the obvious inequality \(e_\varepsilon(f)\geqslant E_\varepsilon(f)\), in estimates (2), (6), (7) one may replace \(e_\varepsilon(f)\) by \(E_\varepsilon(f)\).

  1. The following theorem gives an estimate of the deviation of the partial sums of the Fourier series from an almost-periodic function of class \(S\).

Theorem 3. Let \(0<\eta<\varepsilon,\ f(x)\in S\). Then

\[ R_\varepsilon(f)\leqslant 2E_\varepsilon(f)\left\{1+\frac{2}{\pi}+N_L(\eta)-N_L(\varepsilon)+\frac{1}{\pi}\ln\frac{\varepsilon+\eta}{\varepsilon-\eta}\right\}, \tag{8} \]

where

\[ N_L(\varepsilon)=\sum_{\Lambda_k\geqslant\varepsilon}1. \]

Proof. Let

\[ \varphi_{\eta,\varepsilon}(t)= \begin{cases} 1, & |t|<\eta,\\[4pt] \dfrac{1}{\varepsilon-\eta}(\varepsilon-|t|), & \eta\leqslant |t|\leqslant \varepsilon,\\[6pt] 0, & |t|>\varepsilon; \end{cases} \]

then

\[ \Psi_{\eta,\varepsilon}(u) =\frac{1}{2\pi}\int_{-\infty}^{\infty}\varphi_{\eta,\varepsilon}(t)e^{-iut}\,dt = \frac{2\sin\frac{\varepsilon-\eta}{2}u\,\sin\frac{\varepsilon+\eta}{2}u}{\pi(\varepsilon-\eta)u^2}, \]

\[ f_{\eta,\varepsilon}(x) = \int_{-\infty}^{\infty} f(x+u)\Psi_{\eta,\varepsilon}(u)\,du \sim \sum_{|\Lambda_k|<\eta} A_k e^{i\Lambda_k x} + \sum_{\eta<|\Lambda_k|\leqslant\varepsilon} \varphi_{\eta,\varepsilon}(\Lambda_k)A_k e^{i\Lambda_k x}. \]

It is easy to see that

\[ f(x)-f_{\eta,\varepsilon}(x) = \sum_{\eta<|\Lambda_k|\leqslant\varepsilon} A_k\left[1-\varphi_{\eta,\varepsilon}(\Lambda_k)\right]e^{i\Lambda_k x} + \sum_{|\Lambda_k|>\varepsilon} A_k e^{i\Lambda_k x}, \]

therefore

\[ R_\varepsilon(f)\leqslant \operatorname{Sup}_{x}|f_{\eta,\varepsilon}(x)| + 2\max_{\eta<|\Lambda_k|\leqslant\varepsilon}|A_k|[N(\eta)-N(\varepsilon)+1]. \tag{9} \]

Let \(\varepsilon_1=0\); there exists a function \(F^*(x)\in Q_\varepsilon\) such that

\[ |f(x)-F^*(x)|\leqslant E_\varepsilon(f)+\varepsilon_1. \]

Then

\[ \left| \int_{-\infty}^{\infty} f(x+u)\Psi_{\eta,\varepsilon}(u)\,du - \int_{-\infty}^{\infty} F^*(x+y)\Psi_{\eta,\varepsilon}(u)\,du \right| \leqslant \]

\[ \leqslant [E_\varepsilon(f)+\varepsilon_1]\int_{-\infty}^{\infty}|\Psi_{\eta,\varepsilon}(u)|\,du \leqslant 2[E_\varepsilon(f)+\varepsilon_1]\left(\frac{2}{\pi}+\frac{1}{\pi}\ln\frac{\varepsilon+\eta}{\varepsilon-\eta}\right), \]

and, by the arbitrariness of \(\varepsilon_1\),

\[ |f_{\eta,\varepsilon}(x)| \leqslant 2E_\varepsilon(f)\left(\frac{2}{\pi}+\frac{1}{\pi}\ln\frac{\varepsilon+\eta}{\varepsilon-\eta}\right). \tag{10} \]

For \(|\Lambda_k|\leqslant\varepsilon\),

\[ A_k=\lim_{T\to\infty}\frac{1}{T}\int_0^T [f(x)-F^*(x)]e^{-i\Lambda_k x}\,dx, \]

hence \(|A_k|\leqslant E_\varepsilon(f)+\varepsilon_1\), and, since \(\varepsilon_1\) is arbitrary,

\[ \eta\leqslant \max_{|\Lambda_k|<\varepsilon}|A_k|\leqslant E_\varepsilon(f). \tag{11} \]

From (9), (10), and (11) follows (8).

In applications of Theorem 3, the choice of the parameter $\eta$ is determined to a known extent (see (4)) by the character of the sequence $L(f)$.

  1. Let us consider some applications of the estimates obtained above.

Theorem 4. Let $\theta(x)$ be nonincreasing for $x \geqslant 0$, $\lim\limits_{x\to\infty}\theta(x)=0$, and

\[ \left|\frac{1}{u}\int_0^u f(x+t)\,dt\right|<\theta(|u|). \tag{12} \]

Then the series (1) converges uniformly, if

\[ \lim_{n\to\infty}\theta\!\left(\frac{1}{\Lambda_n}\right)\ln\frac{\Lambda_n+\Lambda_{n+1}}{\Lambda_n-\Lambda_{n+1}}=0. \]

Proof. In consequence of (12), $\Omega_f(N)\leqslant\theta(N)$; applying (2) and (8) with $\varepsilon=\Lambda_n$, $\eta=\Lambda_{n+1}$, we obtain

\[ R_{\Lambda_n}(f)\leqslant 2C_0\theta\!\left(\frac{1}{\Lambda_n}\right) \left(2+\frac{2}{\pi}+\frac{1}{\pi}\ln\frac{\Lambda_n+\Lambda_{n+1}}{\Lambda_n-\Lambda_{n+1}}\right), \]

which proves the theorem.

Theorem 5. Let there exist a constant $A$ such that

\[ \left|\int_0^u f(x+t)\,dt\right|<A. \tag{13} \]

Then the series (1) converges uniformly, if

\[ \Lambda_n\ln\frac{\Lambda_n+\Lambda_{n+1}}{\Lambda_n-\Lambda_{n+1}}=O(1). \tag{14} \]

Proof. By virtue of (13), $f(x)\in S_1$; from (7) and (8) it follows that

\[ R_{\Lambda_n}(f)\leqslant 2C_1\Lambda_n\Omega_{f_1}\!\left(\frac{1}{\Lambda_n}\right) \left(2+\frac{2}{\pi}+\frac{1}{\pi}\ln\frac{\Lambda_n+\Lambda_{n+1}}{\Lambda_n-\Lambda_{n+1}}\right), \]

and, in consequence of (14),

\[ \lim_{n\to\infty} R_{\Lambda_n}(f)=0. \]

From Theorem 4, with $\theta(x)=\dfrac{1}{x^\alpha}$ $(0<\alpha\leqslant 1)$, there follows the convergence criterion of B. M. Levitan $(^{1,2})$. Theorem 5 is a refinement of this criterion for $\alpha=1$.

Theorem 6. If there exist a natural number $m$ and $\theta>1$ such that

\[ \frac{\Lambda_n}{\Lambda_{n+m}}\geqslant \theta \quad (n=1,2,\ldots), \tag{15} \]

then the series (1) converges uniformly.

Proof. From (15) it follows (see $(^3)$) that $N_L(\varepsilon)-N_L(2\varepsilon)=O(1)$. Putting in (8) $\varepsilon=\Lambda_n$, $\eta=\tfrac12\Lambda_n$, we obtain $R_{\Lambda_n}(f)=O[E_{\Lambda_n}(f)]$.

Corollary. Under the condition of Theorem 6, the series (1) converges absolutely $(^{4,5})$; moreover, the order equalities hold

\[ E_\varepsilon(f)\sim R_\varepsilon(f)\sim \alpha_\varepsilon(f), \]

where

\[ \alpha_\varepsilon(f)=\sum_{|\Lambda_k|\leqslant\varepsilon}|A_k|. \]

Kuibyshev
Aviation Institute

Received
1 XII 1959

CITED LITERATURE

$^1$ B. M. Levitan, Zap. Nauch.-issl. inst. matem. i mekh., Kharkovsk. matem. tov., 14, ser. 4, 105 (1937).
$^2$ B. M. Levitan, Almost-periodic functions, Moscow, 1953.
$^3$ S. B. Stechkin, Izv. AN SSSR, ser. matem., 20, No. 3 (1956).
$^4$ E. A. Bredikhina, DAN, 123, No. 2 (1958).
$^5$ E. A. Bredikhina, DAN, 111, No. 6 (1956).

Submission history

Some Questions of Approximation of Almost Periodic Functions with Bounded Spectrum