A PARTICULAR SOLUTION OF THE EQUATIONS OF THE THEORY OF IDEAL PLASTICITY IN CYLINDRICAL COORDINATES
Unknown
Submitted 1964-01-01 | SovietRxiv: ru-196401.68062 | Translated from Russian

Abstract Generated abstract

This paper derives a particular solution of the ideal plasticity equations in cylindrical coordinates under the Huber-Mises yield criterion. Assuming selected independence of the strain-rate tensor and shear stress components from the radial and axial coordinates, the displacement, strain-rate, and stress fields are reduced to expressions involving constants and functions of the angular coordinate. The governing system is transformed into two ordinary differential equations for the angular shear stresses, together with initial conditions and a yield constraint. The resulting family contains fourteen arbitrary constants and includes, as limiting cases, Nadai’s plane deformation solution for plastic flow between inclined rough plates and certain spatial flows between rotating inclined rigid plates.

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THEORY OF ELASTICITY

M. A. ZADOYAN

A PARTICULAR SOLUTION OF THE EQUATIONS OF THE THEORY OF IDEAL PLASTICITY IN CYLINDRICAL COORDINATES

(Presented by Academician L. I. Sedov on 6 II 1964)

The equations of the theory of ideal plasticity under the Huber—Mises plasticity criterion in cylindrical coordinates have the form:

\[ \frac{\partial \sigma_r}{\partial r} +\frac{1}{r}\frac{\partial \tau_{r\theta}}{\partial \theta} +\frac{\partial \tau_{rz}}{\partial z} +\frac{\sigma_r-\sigma_\theta}{r}=0, \]
\[ \frac{\partial \tau_{r\theta}}{\partial r} +\frac{1}{r}\frac{\partial \sigma_\theta}{\partial \theta} +\frac{\partial \tau_{\theta z}}{\partial z} +\frac{2\tau_{r\theta}}{r}=0, \tag{1} \]
\[ \frac{\partial \tau_{rz}}{\partial r} +\frac{1}{r}\frac{\partial \tau_{\theta r}}{\partial \theta} +\frac{\partial \sigma_z}{\partial z} +\frac{\tau_{rz}}{r}=0; \]

\[ (\sigma_r-\sigma_\theta)^2+(\sigma_\theta-\sigma_z)^2+(\sigma_z-\sigma_r)^2 +6\left(\tau_{r\theta}^{\,2}+\tau_{\theta z}^{\,2}+\tau_{rz}^{\,2}\right)=6k^2; \tag{2} \]

\[ \varepsilon_r=\frac{\partial u}{\partial r} =\lambda(2\sigma_r-\sigma_\theta-\sigma_z), \]
\[ \varepsilon_\theta=\frac{u}{r}+\frac{1}{r}\frac{\partial v}{\partial \theta} =\lambda(2\sigma_\theta-\sigma_z-\sigma_r), \tag{3} \]
\[ \varepsilon_z=\frac{\partial w}{\partial z} =\lambda(2\sigma_z-\sigma_r-\sigma_\theta); \]

\[ 2\gamma_{r\theta} =\frac{\partial v}{\partial r}-\frac{v}{r}+\frac{1}{r}\frac{\partial u}{\partial \theta} =6\lambda\tau_{r\theta}, \]
\[ 2\gamma_{\theta z} =\frac{\partial v}{\partial z}+\frac{1}{r}\frac{\partial w}{\partial \theta} =6\lambda\tau_{\theta z}, \tag{4} \]
\[ 2\gamma_{rz} =\frac{\partial u}{\partial z}+\frac{\partial w}{\partial r} =6\lambda\tau_{rz}. \]

From relations (3)—(4) we have

\[ u(r,\theta,z)=u_0(r,z) -\int_{0}^{\theta}\left(r\frac{\partial v}{\partial r}-v\right)d\theta +2r\int_{0}^{\theta}\gamma_{r\theta}\,d\theta; \tag{5} \]

\[ v(r,\theta,z)=v_0(r,z) -\int_{0}^{\theta}u\,d\theta -r\int_{0}^{\theta}(\varepsilon_r+\varepsilon_z)\,d\theta; \tag{6} \]

\[ w(r,\theta,z)=w_0(r,z) -r\int_{0}^{\theta}\frac{\partial v}{\partial z}\,d\theta +2r\int_{0}^{\theta}\gamma_{\theta z}\,d\theta, \tag{7} \]

where \(u_0,\ v_0,\ w_0\) are arbitrary functions of the coordinates \(r\) and \(z\).

Assuming that the strain-rate tensor does not depend on \(r\) and \(z\), we obtain

\[ \varepsilon_r=\frac{\partial u_0}{\partial r}-r\frac{\partial^2 v_0}{\partial r^2}\theta +2\int_0^\theta \gamma_{r\theta}\,d\theta =A_0+A_1\theta+2\int_0^\theta \gamma_{r\theta}\,d\theta; \tag{8} \]

\[ \gamma_{rz}=\frac12\left(\frac{\partial u_0}{\partial z}+\frac{\partial w_0}{\partial r}\right) -r\frac{\partial^2 v_0}{\partial r\,\partial z}\theta +\int_0^\theta \gamma_{\theta z}\,d\theta =C_0+C_1\theta+\int_0^\theta \gamma_{\theta z}\,d\theta; \tag{9} \]

\[ \varepsilon_z=\frac{\partial w_0}{\partial z} -r\int_0^\theta \frac{\partial^2 v}{\partial z^2}\,d\theta, \tag{10} \]

where \(A_0, A_1, C_0, C_1\) are arbitrary constants. From the preceding relations it follows that

\[ \frac{\partial^2 v}{\partial z^2} +\int_0^\theta d\theta\int_0^\theta \frac{\partial^2 v}{\partial z^2}\,d\theta = \frac{\partial^2 v_0}{\partial z^2} -\frac{\partial^2 u_0}{\partial z^2}\theta, \tag{11} \]

and, consequently,

\[ \frac{\partial^2 v}{\partial z^2} = \frac{\partial^2 v_0}{\partial z^2}\cos\theta -\frac{\partial^2 u_0}{\partial z^2}\sin\theta. \tag{12} \]

Substituting (12) into (10), we find

\[ \varepsilon_z = \frac{\partial w_0}{\partial z} +r\frac{\partial^2 u_0}{\partial z^2} -r\frac{\partial^2 v_0}{\partial z^2}\sin\theta -r\frac{\partial^2 u_0}{\partial z^2}\cos\theta = B_0+B_1\sin\theta+B_2\cos\theta;\quad B_0,B_1,B_2=\mathrm{const}. \tag{13} \]

Comparison of relations (8), (9), and (13) leads to the conclusion that the arbitrary constants \(B_1, B_2, C_1\) are equal to zero and to the formulas

\[ u_0(r,z)=A_0r+G_1z+G_0; \tag{14} \]

\[ v_0(r,z)=(A_1+D_1)r-A_1r\ln r+E_1z+E_0; \tag{15} \]

\[ w_0(r,z)=(2C_0-G_1)r+B_0z+D_0, \tag{16} \]

where \(D_1, D_0, E_1, E_0, G_1, G_0\) are new arbitrary constants. Determining from (6) the value of \(r\,\partial v/\partial r-v\) and substituting into (5), we obtain

\[ u+\int_0^\theta d\theta\int_0^\theta u\,d\theta = u_0-\left(r\frac{\partial v_0}{\partial r}-v_0\right)\theta +r\int_0^\theta d\theta\int_0^\theta \varepsilon_r\,d\theta +2r\int_0^\theta \gamma_{r\theta}\,d\theta. \tag{17} \]

Hence

\[ u(r,\theta,z) =(A_0+A_1\theta)r+(E_1z+E_0)\sin\theta +(G_1z+G_0)\cos\theta +2r\int_0^\theta \gamma_{r\theta}\,d\theta. \tag{18} \]

Substitution of (18) into (6) gives

\[ \begin{aligned} v(r,\theta,z) &=(A_1+D_1)r-A_1r\ln r-(2A_0+B_0)r\theta-A_1r\theta^2 \\ &\quad +(E_1z+E_0)\cos\theta-(G_1z+G_0)\sin\theta -4r\int_0^\theta \gamma_{r\theta}(\xi)(\theta-\xi)\,d\xi. \end{aligned} \tag{19} \]

Determining from (6) and (18) that \(\partial v/\partial z=E_1\cos\theta-G_1\sin\theta\), we shall have

\[ w(r,\theta,z) = 2C_0r+B_0z+D_0-(E_1\sin\theta+G_1\cos\theta)r +2r\int_0^\theta \gamma_{r\theta}\,d\theta. \tag{20} \]

With the aid of relations (3)—(4), the stress components are represented in the form

\[ \sigma_r=\sigma_\theta+\frac{2\varepsilon_r+\varepsilon_z}{\gamma_{r\theta}}\tau_{r\theta}, \qquad \sigma_z=\sigma_\theta+\frac{\varepsilon_r+2\varepsilon_z}{\gamma_{r\theta}}\tau_{r\theta}, \qquad \tau_{rz}=\frac{\gamma_{rz}}{\gamma_{r\theta}}\tau_{r\theta}. \tag{21} \]

Substituting (21) into the equilibrium equations (1) and assuming that \(\tau_{r\theta}\) does not

depends on \(r\) and \(z\), we obtain

\[ r\frac{\partial\sigma_\theta}{\partial r} +\frac{\partial\tau_{r\theta}}{\partial\theta} +\sigma_r-\sigma_\theta=0, \]

\[ \frac{\partial\sigma_\theta}{\partial\theta}+2\tau_{r\theta}=0,\qquad r\frac{\partial\sigma_\theta}{\partial z} +\frac{\partial\tau_{\theta z}}{\partial\theta} +\tau_{rz}=0. \tag{22} \]

From the second equation (22) we determine

\[ \sigma_\theta(r,\theta,z)=H(r,z)-2\int_0^\theta \tau_{r\theta}(\theta)\,d\theta, \tag{23} \]

where \(H\) is an arbitrary function of \(r\) and \(z\). Substituting the result into the first and third of equations (22), we obtain \(H=M\ln r+N\), and

\[ \frac{d\tau_{r\theta}}{d\theta} +\frac{2\varepsilon_r+\varepsilon_z}{\gamma_{r\theta}}\tau_{r\theta} +M=0,\qquad \frac{d\tau_{\theta z}}{d\theta} +\frac{\gamma_{rz}}{\gamma_{\theta z}}\tau_{\theta z}=0, \tag{24} \]

where \(M\) and \(N\) are arbitrary constants. From equations (24) and the yield condition (2) the following formulas result:

\[ \gamma_{r\theta}=\frac{\sqrt{3}}{2}B_0\frac{\tau_{r\theta}}{\Omega},\qquad \gamma_{\theta z}=\frac{\sqrt{3}}{2}B_0\frac{\tau_{\theta z}}{\Omega}, \tag{25} \]

\[ \Omega(\theta)= \sqrt{k^2-\tau_{r\theta}^2-\tau_{\theta z}^2-\frac14(\tau'_{r\theta}+M)^2-\tau_{rz}^2}. \tag{26} \]

Using relations (8), (9), (13), and (25), from (24) we obtain

\[ B_0\Omega\frac{d}{d\theta} \left[ \frac{1}{\Omega}\left(\frac{d\tau_{r\theta}}{d\theta}+M\right) \right] +\frac{4A_1}{\sqrt{3}}\Omega +2B_0\tau_{r\theta}=0, \tag{27} \]

\[ \Omega\frac{d}{d\theta} \left[ \frac{1}{\Omega}\frac{d\tau_{\theta z}}{d\theta} \right] +\tau_{\theta z}=0. \tag{28} \]

We also have

\[ \tau'_{r\theta}(0) =-M-(2A_0+B_0) \sqrt{ \frac{k^2-Q_1^2-Q_2^2} {A_0^2+A_0B_0+B_0^2+C_0^2} }, \]

\[ \tau'_{\theta z}(0) =-C_0 \sqrt{ \frac{k^2-Q_1^2-Q_2^2} {A_0^2+A_0B_0+B_0^2+C_0^2} }, \tag{29} \]

where \(Q_1=\tau_{r\theta}(0)\) and \(Q_2=\tau_{\theta z}(0)\) are also arbitrary constants.

Thus, the problem has been reduced to the construction of solutions of a system of two ordinary differential equations. The solution obtained contains 14 arbitrary constants. From it, by taking \(\tau_{\theta z}=\tau_{rz}=B_0=0\), we obtain the known case of plane deformation of a plastic mass between inclined rough plates, investigated by A. Nadai \((^1)\). Setting \(A_1=D_1=E_1=G_1=G_0=E_0=0\), we obtain certain cases of spatial flow of a plastic mass between inclined rigid plates, when the plates rotate with a prescribed velocity about the line of intersection of the contact surfaces. The boundary conditions, analogously to \((^7)\), are satisfied in the integral sense. A somewhat different particular solution in cylindrical coordinates, obtained in this way, is found in the article \((^8)\).

Other particular solutions of spatial problems in cylindrical coordinates having a different structure are given in works \((^{2-6})\).

Institute of Mathematics and Mechanics
Academy of Sciences of the Armenian SSR

Received
3 II 1964

CITED LITERATURE

\(^1\) A. Nadai, Zs. Phys., 30 (1924).
\(^2\) A. Yu. Ishlinskii, Prikl. matem. i mekh., 8, issue 3 (1944).
\(^3\) R. Hill, The Mathematical Theory of Plasticity, Oxford, 1950.
\(^4\) R. T. Shield, Proc. Roy. Soc., A 233, 267 (1955).
\(^5\) D. D. Ivlev, Prikl. matem. i mekh., 22, issue 5 (1958).
\(^6\) D. D. Ivlev, DAN, 123, No. 6 (1958).
\(^7\) M. A. Zadoyan, Izv. AN ArmSSR, ser. fiz.-matem. nauk, No. 3 (1964).
\(^8\) M. A. Zadoyan, Dokl. AN ArmSSR, 39, No. 5 (1964).

Submission history

A PARTICULAR SOLUTION OF THE EQUATIONS OF THE THEORY OF IDEAL PLASTICITY IN CYLINDRICAL COORDINATES