Abstract Generated abstract
This paper studies sufficient conditions for absolute convergence of Fourier series of periodic functions in terms of symmetric finite differences and related integral moduli of smoothness. It proves coefficient tail estimates for \(0<m\leq 2\), bounding sums of powers of Fourier coefficients by quantities involving averaged \(p\)th symmetric differences in \(L^2\). These estimates yield conditions for absolute convergence and rates of decay under smoothness assumptions such as Lipschitz conditions on derivatives. Further corollaries show that the results include and strengthen several classical criteria based on bounded variation, second variation, and moduli of continuity.
Full Text
V. V. Zhuk
On the Absolute Convergence of Fourier Series
(Presented by Academician S. N. Bernstein, July 15, 1964)
Let \(f(x)\in L^2_{2\pi}\) be a \(2\pi\)-periodic function. Put
\[ {}^{s}\Delta_t^p f(x)=\sum_{k=0}^{p}(-1)^k C_p^k f[x+(p-2k)t], \]
\[ L^{(p)}(h,x,f)=\frac{1}{h}\int_0^h {}^{s}\Delta_t^p f(x)\,dt, \]
\[ L_2^{(p)}(h,f)=\frac{1}{h}\left\{\sup_{0\le u\le h}\int_{-\pi}^{\pi}\left[\int_0^u {}^{s}\Delta_t^p f(x)\,dt\right]^2 dx\right\}^{1/2}, \]
\[ {}^{s}\omega_p(h,f)=\sup_{0\le t\le h}\ \sup_{-\pi\le x\le \pi}\left|{}^{s}\Delta_t^p f(x)\right|, \]
\[ {}^{s}\omega_p^{(2)}(h,f)=\left\{\sup_{0\le t\le h}\int_{-\pi}^{\pi}\left[{}^{s}\Delta_t^p f(x)\right]^2 dx\right\}^{1/2}. \]
Lemma 1. Suppose
\[ f(x)\sim \frac{a_0}{2}+\sum_{k=1}^{\infty}(a_k\cos kx+b_k\sin kx). \]
Then
\[ \frac{1}{n^{2p}}\sum_{k=1}^{n}(a_k^2+b_k^2)k^{2p}\le C(p)\int_{-\pi}^{\pi}\left[L^{(p)}\left(\frac{1}{n},x,f\right)\right]^2 dx, \]
where \(p\) is any natural number, and \(C(p)\) is a constant depending only on \(p\).
Lemma 2. If \(0<m\le 2\), then
\[ \sum_{k=2^{\gamma-1}+1}^{2^\gamma}\left(|a_k|^m+|b_k|^m\right) \le C_1(p)\left\{\int_{-\pi}^{\pi}\left[L^{(p)}\left(\frac{1}{2^\gamma},x,f\right)\right]^2 dx\right\}^{m/2}(2^\gamma)^{1-m/2}, \]
where \(p\) and \(\gamma\) are any natural numbers, and \(C_1(p)\) is a constant depending only on \(p\).
Lemma 3. If \(2^{l-1}\le n<2^l\), then
\[ \sum_{k=n}^{\infty} k^{\alpha-1}E\left(\frac{1}{k}\right) \ge C(\alpha)\sum_{\gamma=l+1}^{\infty}(2^\gamma)^\alpha E\left(\frac{1}{2^\gamma}\right), \]
where \(E\left(\frac{1}{k}\right)\downarrow 0\) as \(k\uparrow\infty\); \(\alpha\) is any real number; \(C(\alpha)\) is a constant depending only on \(\alpha\); \(n\) and \(l\) are natural numbers.
Theorem 1. If \(0<m\leqslant 2\), then
\[ \sum_{k=n}^{\infty}\left(|a_k|^m+|b_k|^m\right)\leqslant \]
\[ \leqslant C(p,m)\left\{\sum_{k=n}^{\infty} \frac{\left[L_2^{(p)}\left(\frac1k,f\right)\right]^m}{k^{m/2}} +\left[L_2^{(p)}\left(\frac1n,f\right)\right]^m n^{1-m/2}\right\}, \]
where \(C(p,m)<+\infty\) is a constant depending only on \(p\) and \(m\).
Proof. Let \(2^{l-1}\leqslant n<2^l\). Then
\[ \sum_{k=n}^{\infty}\left(|a_k|^m+|b_k|^m\right) \leqslant \sum_{k=n}^{2^l}\left(|a_k|^m+|b_k|^m\right) +\sum_{\gamma=l+1}^{\infty}\sum_{k=2^{\gamma-1}+1}^{2^\gamma} \left(|a_k|^m+|b_k|^m\right) = \]
\[ =O\left( \sum_{k=n}^{2n}\left(|a_k|^m+|b_k|^m\right) + \sum_{\gamma=l+1}^{\infty} \left\{ \int_{-\pi}^{\pi} \left[L^{(p)}\left(\frac1{2^\gamma},x,f\right)\right]^2 dx \right\}^{m/2} (2^\gamma)^{1-m/2} \right)=I_1+I_2. \]
Let us estimate \(I_1\):
\[ \sum_{k=n}^{2n}\left(|a_k|^m+|b_k|^m\right) \leqslant \left\{\sum_{k=n}^{2n}(a_k^2+b_k^2)\right\}^{m/2} n^{1-m/2} \leqslant \]
\[ \leqslant C_2(p)\left\{ \int_{-\pi}^{\pi} \left[L^{(p)}\left(\frac1{2n},x,f\right)\right]^2 dx \right\}^{m/2} n^{1-m/2} \leqslant C_3(p)\left[L_2^{(p)}\left(\frac1n,f\right)\right]^m n^{1-m/2}. \]
Passing to the estimate of \(I_2\), we have
\[ \sum_{\gamma=l+1}^{\infty} \left\{ \int_{-\pi}^{\pi} \left[L^{(p)}\left(\frac1{2^\gamma},x,f\right)\right]^2 dx \right\}^{m/2} (2^\gamma)^{1-m/2} \leqslant \sum_{\gamma=l+1}^{\infty} \left[L_2^{(p)}\left(\frac1{2^\gamma},f\right)\right]^m (2^\gamma)^{1-m/2}. \]
Applying* Lemma 3, we obtain
\[ \sum_{\gamma=l+1}^{\infty} \left[L_2^{(p)}\left(\frac1{2^\gamma},f\right)\right]^m (2^\gamma)^{1-m/2} \leqslant C(m)\sum_{k=n}^{\infty} \frac{\left[L_2^{(p)}\left(\frac1k,f\right)\right]^m}{k^{m/2}}. \]
The rest is clear.
Corollary 1. It is not hard to verify that
\[ L_2^{(p)}(h,f)\leqslant { }^{s}\omega_p^{(2)}(h,f). \]
Consequently, for \(0<m\leqslant 2\),
\[ \sum_{k=n}^{\infty}\left(|a_k|^m+|b_k|^m\right) = O\left( \sum_{k=n}^{\infty} \frac{\left[{ }^{s}\omega_p^2\left(\frac1k,f\right)\right]^m}{k^{m/2}} \right) + \left[{ }^{s}\omega_p^{(2)}\left(\frac1n,f\right)\right]^m n^{1-m/2}. \]
In particular, if \(f(x)\) has \(l\) derivatives, \(f^{(l)}(x)\in \mathrm{Lip}\,\alpha\), and \(m(l+\alpha)+m/2>1\), then
\[ \sum_{k=n}^{\infty}\left(|a_k|^m+|b_k|^m\right) = O\left(n^{\,1-m(l+\alpha+1/2)}\right). \]
For \(l=0\) this is a result of Lorentz \((^1)\).
\[ * \ \text{For } E\left(\frac1k\right) \text{ we take } \left\{ \sup_{0\leqslant u\leqslant 1/k} \int_{-\pi}^{\pi} \left[ \int_0^u { }^{s}\Delta_t^p f(x)\,dt \right]^2 dx \right\}^{1/2}. \]
Corollary 2. If
\[ \sup_{0<t\leq 1/n}\int_{-\pi}^{\pi}\left|\,{}^{s}\Delta_t^p f(x)\right|\,dx =O\left(\frac1n\right),\qquad \sum_{k=1}^{\infty}\frac{\left[{}^{s}\omega_p\left(\frac1k,f\right)\right]^{1/2}}{k}<+\infty, \]
then
\[ \sum_{k=1}^{\infty}\bigl(|a_k|+|b_k|\bigr)<+\infty . \tag{1} \]
From this, in particular, the following two theorems follow:
Theorem A (A. Zygmund \((^2)\)). If \(f(x)\) has bounded variation and*
\[ \sum_{k=1}^{\infty} \frac{\sqrt{\omega\left(\frac1k,f\right)}}{k}<+\infty, \]
where
\[ \omega(\delta,f)=\sup_{|x_1-x_2|<\delta}|f(x_1)-f(x_2)|, \]
then relation (1) is satisfied.
Theorem B (F. I. Harshiladze \((^4)\)). If \(f(x)\) is such that for all \(x\) and \(h\)
\[ |f(x+h)+f(x-h)-2f(x)|\leq Mh^\alpha \]
with \(\alpha>0\), and, moreover, \(f(x)\) has bounded second variation on \([0,2\pi]\), then its Fourier series converges absolutely.
Indeed, Theorem A is obvious, while Theorem B follows from the equality
\[ \int_{-\pi}^{\pi}|f(x+t)-2f(x)+f(x-t)|\,dx=O(t), \tag{2} \]
which is valid whenever \(f(x)\) has bounded second variation \((^5)\). Since \((^6)\) it does not follow from (2) that \(f\in V_2\), it is clear that Corollary 2 is stronger than Theorems A and B.
Let \(F(x)\) be an antiderivative of \(f(x)\).
Theorem 1. If
\[ \sum_{k=1}^{\infty} k^{1/2}\omega_2^{(2)}\left(F,\frac1k\right)<+\infty, \]
then relation (1) is satisfied.
Corollary 1. (Theorem of Sas \((^7)\)). If
\[ \sum_{k=1}^{\infty}\frac{\omega_1^{(2)}(1/k,f)}{\sqrt{k}}<+\infty, \]
then relation (1) is satisfied.
Corollary 2. From
\[ \sum_{k=1}^{\infty} \left\{ k\,{}^{s}\omega_2\left(F,\frac1k\right) \sup_{0<t\leq 1/k} \int_{-\pi}^{\pi}|F(x+t)-2F(x)+F(x-t)|\,dx \right\}^{1/2}<+\infty \]
it follows that (1) holds.
Corollary 3. If
\[ \sum_{k=1}^{\infty}\sqrt{k}\,{}^{s}\omega_2\left(F,\frac1k\right)<+\infty, \]
then (1) holds.
* The assertion formulated in the text is due to Salem \((^3)\), who notes that it follows immediately from Zygmund’s results.
Hence it follows
Theorem (S. N. Bernstein \(^{8}\)). The relation
\[ \sum_{k=1}^{\infty} \frac{\omega(1/k,f)}{\sqrt{k}} < +\infty \]
implies (1).
Corollary 4. If
\[ \sup_{0\le t\le 1/n}\int_{-\pi}^{\pi} \left|F(x+t)-2F(x)+F(x-t)\right|\,dx =O\left(\frac{1}{n^{2}}\right), \]
then from
\[ \sum_{k=1}^{\infty}\frac{\sqrt[5]{\omega_{2}(F,1/k)}}{\sqrt{k}}<+\infty \]
follows (1).
This assertion contains the theorem of A. Zygmund mentioned above.
Leningrad State University
named after A. A. Zhdanov
Received
12 VI 1964
REFERENCES
\(^{1}\) G. G. Lorentz, Math. Zs., 51, 135 (1948).
\(^{2}\) A. Zygmund, J. London Math. Soc., 3, 194 (1928).
\(^{3}\) R. Salem, Duke Math. J., 10, 23 (1943).
\(^{4}\) F. I. Kharshiladze, DAN, 79, No. 2, 201 (1951).
\(^{5}\) F. I. Kharshiladze, Tr. Tbilissk. matem. inst., 20, 145 (1954).
\(^{6}\) F. I. Kharshiladze, Tr. Tbilissk. univ., 64, 94 (1957).
\(^{7}\) O. Szász, Ann. Math., 47, 213 (1946).
\(^{8}\) S. N. Bernstein, Collected Works, 2, 1954, pp. 166–169.