INTEGRABILITY CONDITIONS IN FINITE FORM FOR CERTAIN SYSTEMS OF ORDINARY DIFFERENTIAL EQUATIONS OF THE SECOND ORDER
V. G. Skatetskii
Submitted 1966 | SovietRxiv: ru-196601.29864 | Translated from Russian

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UDC 517.934.92

INTEGRABILITY CONDITIONS IN FINITE FORM FOR CERTAIN SYSTEMS OF ORDINARY DIFFERENTIAL EQUATIONS OF THE SECOND ORDER

V. G. Skatetskii

Consider the system

\[ \frac{dX}{dt}=X\left(U_0\varphi_0+U_1\varphi_1+U_0U_1\varphi_2+U_1U_0\varphi_3\right), \tag{1} \]

where \(U_i\) \((i=0,1)\) are matrices of the second order, whose determinants and traces \(\sigma(U_i)\) are equal to zero; \(\varphi_i\) \((i=0,1,2,3)\) are continuous scalar functions of \(t\).

We shall show that if the functions \(\varphi_0\) and \(\varphi_1\) satisfy the condition

\[ \varphi_0=-\frac{\sigma_{01}}{\sigma_0}(\varphi_2+\varphi_3), \qquad \varphi_1=-\frac{\sigma_0}{(a+b)^2}(a^2\varphi_2+b^2\varphi_3), \tag{2} \]

where \(\sigma_0,\sigma_{01}\) are the nonzero traces of the corresponding matrices \(U_0, U_0U_1\), and \(a\) and \(b\) are arbitrary numbers satisfying the condition \(a+b\ne0\), \(a\ne0\), \(b\ne0\), then system (1) has a solution of the form

\[ X=\exp\left[A\int_{t_0}^{t} F_1\exp(2L_2)\,d\tau\right]\exp(BL_2), \tag{3} \]

where

\[ L_2=\int_{t_0}^{t}F_2\,d\tau; \]

\[ A=-\frac{(a+b)\sigma_{01}}{\sigma_0}U_0-\frac{ab\sigma_0}{a+b}U_1+bU_0U_1+aU_1U_0, \]

\[ B=\frac{a+b}{b\sigma_0}U_0+\frac{b\sigma_0}{(a+b)\sigma_{01}}U_1-\frac{a+b}{b\sigma_{01}}U_1U_0, \tag{4} \]

\[ F_1=\frac{\varphi_2}{b}, \qquad F_2=\frac{\sigma_{01}}{a+b}(a\varphi_2-b\varphi_3). \tag{5} \]

We shall carry out the proof in the same way as in [1]. We shall show that the identity

\[ 2AB\dot{A}=A^2B+\dot{B}A^2 \tag{6} \]

holds.

Indeed, by computation, using the properties of the matrices \(U_0\) and \(U_1\), considered in [2], one can show that \(A^2=0\), \(BA=A\), \(AB=-A\). Hence it is clear that identity (6) holds.

On the basis of [3] (pp. 52–53), the system

\[ \frac{dX}{dt}=X(AF_1+BF_2), \tag{7} \]

where \(A\) and \(B\) are determined by formulas (4); in this case there will be a solution of the form (3).

System (7) can be rewritten as

\[ \frac{dX}{dt} = X\left[ \frac{a+b}{\sigma_0} \left( -\sigma_{01}F_1+\frac{1}{b}F_2 \right)U_0 + \frac{b\sigma_0}{a+b} \left( -aF_1+\frac{1}{\sigma_{01}}F_2 \right)U_1 + \right. \]
\[ \left. + bF_1U_0U_1 + \left( aF_1-\frac{a+b}{b\sigma_{01}}F_2 \right)U_1U_0 \right]. \tag{8} \]

In order that system (1) be equivalent to system (8), it is necessary and sufficient that the following equalities hold:

\[ \frac{a+b}{\sigma_0} \left( -\sigma_{01}F_1+\frac{1}{b}F_2 \right)=\varphi_0, \qquad \frac{b\sigma_0}{a+b} \left( -aF_1+\frac{1}{\sigma_{01}}F_2 \right)=\varphi_1, \]

\[ bF_1=\varphi_2, \qquad aF_1-\frac{a+b}{b\sigma_{01}}F_2=\varphi_3. \]

From the last two equalities we obtain expression (5). Substituting the obtained values of \(F_1\) and \(F_2\) into the first two equalities of the latter relations, we obtain the sufficient conditions (2).

Let us now consider a system of the following form:

\[ \frac{dX}{dt}=X(U_0\varphi_0+U_1\varphi_1+U_2\varphi_2), \tag{9} \]

where \(U_i\) \((i=0,1,2)\) are matrices of the second order whose determinants and the trace \(\sigma(U_1)\) are equal to zero; \(\varphi_i\) \((i=0,1,2)\) are continuous scalar functions of \(t\); \(\sigma_0\ne0\), \(\sigma_{01}\ne0\). According to [2] and taking into account the identities

\[ U_1U_0=-U_0U_1+\sigma_0U_1+\sigma_{01}, \]

\[ U_2= \frac{\sigma_{12}}{\sigma_{01}}U_0 + \frac{\sigma_{01}\sigma_{02}-\sigma_0(\sigma_{012}+\sigma_{102})}{\sigma_{01}^{2}}U_1 + \]

\[ + \frac{\sigma_{012}U_0U_1+\sigma_{102}U_1U_0}{\sigma_{01}^{2}} + \sigma_2-\frac{\sigma_{012}+\sigma_{102}}{\sigma_{01}}, \]

considered in [2], system (9) can be written as

\[ \frac{dX}{dt} = X\left\{ \left(\varphi_0+\frac{\sigma_{12}}{\sigma_{01}}\varphi_2\right)U_0 + \left(\varphi_1+ \frac{\sigma_{01}\sigma_{02}-\sigma_0\sigma_{012}}{\sigma_{01}^{2}}\varphi_2 \right)U_1 + \right. \]

\[ \left. + \frac{\sigma_{012}-\sigma_{102}}{\sigma_{01}^{2}}\varphi_2U_0U_1 + \left(\sigma_2-\frac{\sigma_{012}}{\sigma_{01}}\right)\varphi_2 \right\}, \]

where \(\sigma_{12}\), \(\sigma_{02}\), \(\sigma_{012}\), and \(\sigma_{102}\) are the traces of the corresponding matrices \(U_1U_2\), \(U_0U_2\), \(U_0U_1U_2\), and \(U_1U_0U_2\). Applying to the last system the substitution

\[ X = Y\exp\left[ \left(\sigma_2-\frac{\sigma_{012}}{\sigma_{01}}\right) \int_{t_0}^{t}\varphi_2\,dt \right] \]

under the condition that

\[ \sigma_2\ne\frac{\sigma_{012}}{\sigma_{01}}, \]

we obtain

\[ \frac{dY}{dt}=Y\left\{\left(\varphi_0+\frac{\sigma_{12}}{\sigma_{01}}\varphi_2\right)U_0+ \left(\varphi_1+\frac{\sigma_{01}\sigma_{02}-\sigma_0\sigma_{012}}{\sigma_{01}^{2}}\varphi_2\right)U_1+ \frac{\sigma_{012}-\sigma_{102}}{\sigma_{01}^{2}}\varphi_2U_0U_1\right\}. \tag{10} \]

Arguing in the same way, taking into account for the matrices \(U_0\) and \(U_1\) the identities indicated above and applying the substitution

\[ X=Y\exp\left[\int_{t_0}^{t}\left(a\sigma_{01}F_1-\frac{a+b}{b}F_2\right)d\tau\right], \]

in the present case the system (7) can be transformed to the form

\[ \frac{dY}{dt}=Y\left\{\left[-\frac{(a+b)\sigma_{01}}{\sigma_0}F_1+ \frac{a+b}{b\sigma_0}F_2\right]U_0+\right. \]

\[ \left.+\left[\frac{a^2\sigma_0}{a+b}F_1- \frac{a\sigma_0(a+2b)}{b(a+b)\sigma_{01}}F_2\right]U_1+ \left[(b-a)F_1+\frac{a+b}{b\sigma_{01}}F_2\right]U_0U_1\right\}. \tag{11} \]

The solution of this system has the form

\[ Y=X\exp\left[-\int_{t_0}^{t}\left(a\sigma_{01}F_1-\frac{a+b}{b}F_2\right)d\tau\right], \tag{12} \]

where \(X\) is determined by formula (3).

In order that system (10) be equivalent to system (11), it is necessary and sufficient that the equalities

\[ \frac{a+b}{\sigma_0}\left(-\sigma_{01}F_1+\frac{1}{b}F_2\right) =\varphi_0+\frac{\sigma_{12}}{\sigma_{01}}\varphi_2, \]

\[ \frac{a\sigma_0}{a+b}\left(aF_1-\frac{a+2b}{b\sigma_{01}}F_2\right) =\varphi_1+\frac{\sigma_{01}\sigma_{02}-\sigma_0\sigma_{012}}{\sigma_{01}^{2}}\varphi_2, \tag{13} \]

\[ (b-a)F_1+\frac{a+b}{b\sigma_{01}}F_2 =\frac{\sigma_{012}-\sigma_{102}}{\sigma_{01}^{2}}\varphi_2. \]

Finding \(F_1\) and \(F_2\) from the first two equations of system (13),

\[ F_1=-\frac{(a+2b)\sigma_0}{2b(a+b)\sigma_{01}}\varphi_0 -\frac{a+b}{2ab\sigma_0}\varphi_1+ \]

\[ +\frac{(a+b)^2(\sigma_0\sigma_{012}-\sigma_{01}\sigma_{02})-\sigma_0^2\sigma_{12}a(a+2b)} {2ab(a+b)\sigma_0\sigma_{01}^{2}}\varphi_2, \tag{14} \]

\[ F_2=-\frac{a\sigma_0}{2(a+b)}\varphi_0 -\frac{\sigma_{01}(a+b)}{2a\sigma_0}\varphi_1- \]

\[ -\frac{(a+b)^2(\sigma_{01}\sigma_{02}-\sigma_0\sigma_{012})+a^2\sigma_0^2\sigma_{12}} {2a(a+b)\sigma_0\sigma_{01}}\varphi_2 \]

and substituting them into the third equation of system (13), we obtain that

\[ \varphi_0=-\frac{(a+b)^2\sigma_{01}}{ab\sigma_0^2}\,\varphi_1- \]

\[ -\frac{ab\sigma_0^2\sigma_{12}+(a+b)\left[(a+b)\sigma_{01}\sigma_{02}-\sigma_0(a\sigma_{102}+b\sigma_{012})\right]}{ab\sigma_0^2\sigma_{01}}\,\varphi_2 . \tag{15} \]

Thus, the following result has been obtained: if \(\varphi_0\) satisfies condition (15), then system (10) has a solution of the form (12), where \(F_1\) and \(F_2\) are determined by formulas (14), and \(A\) and \(B\) by formulas (4).

Remark. Let a system be given

\[ \frac{dX}{dt}=X\sum_{i=0}^{n}U_i\varphi_i, \tag{16} \]

where \(U_i\) \((i=0,1,\ldots,n)\) are matrices of the second order, the determinants of which and the trace of one of them are equal to zero. Without loss of generality, we assume that \(\sigma(U_1)=0\), and that \(\varphi_i\) are continuous scalar functions of \(t\). As before, we assume that \(\sigma_0\ne0\) and \(\sigma_{01}\ne0\). According to [1] and [2], this system can be written in the following form:

\[ \frac{dY}{dt} = Y\left\{ \left(\varphi_0+\sum_{i=2}^{n}\frac{\sigma_{1i}}{\sigma_{01}}\varphi_i\right)U_0+ \right. \]

\[ \left. +\left(\varphi_1+\sum_{i=2}^{n}\frac{\sigma_{01}\sigma_{0i}-\sigma_0\sigma_{01i}}{\sigma_{01}^{2}}\varphi_i\right)U_1 +\sum_{i=2}^{n}\frac{\sigma_{01i}-\sigma_{10i}}{\sigma_{01}^{2}}\varphi_i U_0U_1 \right\}, \]

where \(\sigma_{1i}\), \(\sigma_{01i}\), and \(\sigma_{10i}\) are the traces of the corresponding matrices \(U_1U_i\), \(U_0U_1U_i\), and \(U_1U_0U_i\). System (16) is integrable in finite form if the relation

\[ \varphi_0=-\frac{(a+b)^2\sigma_{01}}{ab\sigma_0^2}\,\varphi_1- \]

\[ -\sum_{i=2}^{n} \frac{ab\sigma_0^2\sigma_{0i}+(a+b)\left[(a+b)\sigma_{01}\sigma_{0i}-\sigma_0(a\sigma_{10i}+b\sigma_{01i})\right]} {ab\sigma_0^2\sigma_{01}}\, \varphi_i, \]

is satisfied, and the integral matrix \(Y\) is determined by formula (12), where \(F_1\) and \(F_2\) have the form:

\[ F_1 = -\frac{(a+2b)\sigma_0}{2b(a+b)\sigma_{01}}\varphi_0 -\frac{a+b}{2ab\sigma_0}\varphi_1+ \]

\[ +\sum_{i=2}^{n} \frac{(a+b)^2(\sigma_0\sigma_{01i}-\sigma_{01}\sigma_{0i})-\sigma_0^2\sigma_{1i}a(a+2b)} {2ab(a+b)\sigma_0\sigma_{01}^{2}}\, \varphi_i, \]

\[ F_2 = -\frac{a\sigma_0}{2(a+b)}\varphi_0 -\frac{(a+b)\sigma_{01}}{2a\sigma_0}\varphi_1- \]

\[ -\sum_{i=2}^{n} \frac{(a+b)^2(\sigma_{01}\sigma_{0i}-\sigma_0\sigma_{01i})+a^2\sigma_0^2\sigma_{1i}} {2a(a+b)\sigma_0\sigma_{01}}\, \varphi_i . \]

References

  1. Fedorov G. F. Vestnik LGU, No. 11, 57–65, 1953.
  2. Fedorov G. F. Izv. vuzov, No. 3, 217–224, 1958.
  3. Erugin N. P. Linear Systems of Ordinary Differential Equations. Minsk, 1963.

Received by the editors
November 19, 1965

Institute of Mathematics of the Academy of Sciences of the BSSR

Submission history

INTEGRABILITY CONDITIONS IN FINITE FORM FOR CERTAIN SYSTEMS OF ORDINARY DIFFERENTIAL EQUATIONS OF THE SECOND ORDER