Abstract Generated abstract
This note establishes several sum theorems for the large inductive dimension Ind in normal Hausdorff spaces, weakening earlier hereditary normality assumptions by imposing conditions on intersections or on normally situated closed subsets. It proves that a normal space that is the union of closed subspaces of dimension at most n has dimension at most n under zero-dimensional intersection hypotheses, and applies this to show that the product of two bicompact spaces of Ind at most 1 has Ind at most 2. The paper also introduces normally situated and normally Ind-lying closed sets, proves corresponding extension theorems for Ind, and recovers Dowker-type results as consequences in the hereditarily normal case.
Full Text
UDC 513.831
MATHEMATICS
I. K. LIFANOV
SOME THEOREMS CONCERNING THE DIMENSION Ind
(Presented by Academician P. S. Aleksandrov on 13 I 1967)
Dauker \((^1)\) proves sum theorems for \(\operatorname{Ind}\) * for hereditarily normal spaces. In this note we free ourselves from the condition of hereditary normality ** of the spaces participating in the sum, but impose conditions on the intersections of these spaces.
Theorem 1. If a normal space \(P=X\cup Y\) is the sum of two closed subsets \(X\) and \(Y\) such that: 1) \(\operatorname{Ind}X\le n\), \(\operatorname{Ind}Y\le n\); 2) \(\operatorname{Ind}(X\cap Y)\le 0\), then \(\operatorname{Ind}P\le n\).
Proof. Let \(F=X\cap Y\). Take a closed set \(\Phi\) in \(P\) and an arbitrary neighborhood \(O\Phi\) of it.
a) If \(\Phi\cap F=\varnothing\), then for \(O\Phi\) there will be found a neighborhood \(O_1\Phi\) of the set \(\Phi\) such that \([O_1\Phi]\cap F=\varnothing\), \(O_1\Phi\subseteq O\Phi\), and \(\operatorname{Ind}\operatorname{fr}O_1\Phi\le n-1\).
b) Let now \(\Phi\cap F\ne\varnothing\). Put \(\Phi_1=\Phi\cap F\), \(O_F\Phi_1=O\Phi\cap F\), where the subscript \(F\) indicates in which set this \(O_F\Phi_1\) is open.
Since \(\operatorname{Ind}F\le 0\), there will be found an open-and-closed neighborhood \(O_F^1\Phi_1\) of the set \(\Phi_1\), contained in \(O_F\Phi_1\).
Consider the sets \(\Phi_2=\Phi\cup O_F^1\Phi_1\) and \(\Phi_2'=(P\setminus O\Phi)\cup F_1\), where \(F_1=F\setminus O_F^1\Phi_1\). The sets \(\Phi_2\) and \(\Phi_2'\) are closed in \(P\), and \(\Phi_2\cap\Phi_2'=\varnothing\). Next take the sets \(X_1=X\cap\Phi_2\), \(X_1'=X\cap\Phi_2'\) and the sets \(Y_1=Y\cap\Phi_2\), \(Y_1'=Y\cap\Phi_2'\). The sets \(X_1, X_1'\) (\(Y_1, Y_1'\)) are closed in \(X\) (\(Y\)) and \(X_1'\cap X_1=\varnothing\) (\(Y_1\cap Y_2'=\varnothing\)); therefore, in view of the fact that \(\operatorname{Ind}X\le n\), \(\operatorname{Ind}Y\le n\), there will be found a neighborhood \(\Gamma_1\) (\(\Gamma_2\)) of the set \(X_1\) (\(Y_1\)) in \(X\) (\(Y\)) such that \(\operatorname{Ind}\operatorname{fr}\Gamma_1\le n-1\) (\(\operatorname{Ind}\operatorname{fr}\Gamma_2\le n-1\)) and \([\Gamma_1]_X\cap X_1'=\varnothing\) (\([\Gamma_2]_Y\cap Y_1'=\varnothing\)). From the choice of the sets \(\Gamma_1\) and \(\Gamma_2\) it is clear that the set \(\Gamma=\Gamma_1\cup\Gamma_2\) is open in \(P\), since \(\Gamma_1\cap Y=\Gamma_2\cap X\). Moreover, \(\operatorname{fr}_P\Gamma_1\cap\operatorname{fr}_P\Gamma_2=\varnothing\), since \(\operatorname{fr}_P\Gamma_1\subset X\), \(\operatorname{fr}_P\Gamma_2\subset Y\) and \(\operatorname{fr}_P\Gamma_1\cap F=\operatorname{fr}_P\Gamma_2\cap F=\varnothing\), while \(\operatorname{fr}_P\Gamma_1\cup\operatorname{fr}_P\Gamma_2\) is closed. Then \(\operatorname{Ind}\operatorname{fr}_P\Gamma\le n-1\) and \(\Phi\subset \Gamma\subset O\Phi\). Thus theorem 1 is proved.
From theorem 1 it follows
Theorem 2. Let a normal space
\[
P=\bigcup_{i=1}^n X_i,
\]
where: 1) \(X_i\) is closed in \(P\); 2) \(\operatorname{Ind}(X_i\cap X_j)\le 0\) for \(i\ne j\) \((i=1,2,\ldots,n;\ j=1,2,\ldots,n)\); 3) \(\operatorname{Ind}X_i\le n\) \((i=1,2,\ldots,n)\). Then \(\operatorname{Ind}P\le n\).
Using theorem 2, we shall now prove theorem 3.
Theorem 3. Let \(P=X\times Y\), where \(X,Y\) are bicompacts and \(\operatorname{Ind}X\le 1\), \(\operatorname{Ind}Y\le 1\). Then \(\operatorname{Ind}P\le 2\).
We shall first prove a lemma.
Lemma 1. Let \(X\) be a one-dimensional bicompact, \(\operatorname{Ind}X\le 1\), and let \(\omega=\{O_1,O_2,\ldots,O_s\}\) be an arbitrary open covering. Then one can construct a refinement *** \(\alpha=\{A_1,A_2,\ldots,A_s\}\), inscribed in \(\omega\), satisfying the condition \(\operatorname{Ind}\operatorname{fr}(\operatorname{Int}A_j)\le 0\).
* A space \(X\) has \(\operatorname{Ind}X\le n\) if for every closed set \(F\) and every neighborhood \(OF\) of it there exists \(O_1F\subset OF\) such that \(\operatorname{Ind}\operatorname{fr}O_1F\le n-1\), \(\operatorname{Ind}\varnothing=-1\).
** All spaces considered in the note are assumed to be Hausdorff and normal.
* A covering \(\alpha=\{A_1,A_2,\ldots,A_s\}\) of a space \(X\) is called a partition if \(A_i=[\operatorname{Int}A_i]\) and \(\operatorname{Int}A_i\cap\operatorname{Int}A_j=\varnothing\) for \(i\ne j\) \((i,j=1,2,\ldots,n)\).
Proof. Take an arbitrary open cover
\(\omega=\{O_1,O_2,\ldots,O_s\}\). In \(\omega\) inscribe such an open cover
\(\omega^1=\{O_1^1,O_2^1,\ldots,O_s^1\}\) that \([O_i^1]\subseteq O_i\) and
\(\operatorname{Ind}\operatorname{Fr} O_i^1\leq 0,\ i=1,2,\ldots,s\).
Define by induction the sets \(A_i\) \((i=1,2,\ldots,s)\),
\[
\operatorname{Int} A_1
=
O_1^1\setminus \bigcup_{i=2}^{s}[O_i^1],\qquad
A_1=[\operatorname{Int} A_1],
\]
then
\[
A_1\cup \bigcup_{i=2}^{s} O_i^1=X
\quad\text{and}\quad
\operatorname{Ind}\operatorname{Fr}(\operatorname{Int} A_1)\leq 0,
\]
since
\[
\operatorname{Fr}(\operatorname{Int} A_1)\subseteq \bigcup_{i=1}^{s}\operatorname{Fr} O_i^1 .
\]
Suppose that we have already constructed sets \(A_1,A_2,\ldots,A_{k-1}\) satisfying the conditions:
\[
\text{a) }\quad
\operatorname{Int} A_{i_1}\cap \operatorname{Int} A_{i_2}=\varnothing
\quad\text{for } i_1\ne i_2\ (i_1,i_2=1,2,\ldots,k-1);
\]
\[
\text{b) }\quad
\bigcup_{j=1}^{k-1} A_j\cup \bigcup_{i=k}^{s} O_i^1=X;
\]
\[
\text{c) }\quad
\operatorname{Fr}\operatorname{Int} A_j\subseteq
\bigcup_{i=1}^{s}\operatorname{Fr} O_i^1
\quad (j=1,2,\ldots,k-1).
\]
Construct \(A_k\):
\[
\operatorname{Int} A_k
=
O_k^1\setminus
\left(\bigcup_{i=k+1}^{s}[O_i^1]\cup \bigcup_{j=1}^{k-1} A_j\right),
\qquad
A_k=[\operatorname{Int} A_k].
\]
Then, by the definition of the set \(A_k\), we obtain:
\[
\text{a) }\quad
\bigcup_{j=1}^{k} A_j\cup \bigcup_{i=k+1}^{s} O_i^1=X.
\]
Further,
\[
\operatorname{Fr}\operatorname{Int} A_k
\subseteq
\bigcup_{i=k}^{s}\operatorname{Fr} O_i^1
\cup
\bigcup_{i=1}^{k-1}\operatorname{Fr}\operatorname{Int} A_j,
\]
but
\[
\operatorname{Fr}\operatorname{Int} A_j\subseteq
\bigcup_{i=1}^{s}\operatorname{Fr} O_i^1
\quad (j=1,2,\ldots,k-1),
\]
therefore
\[
\text{b) }\quad
\operatorname{Fr}\operatorname{Int} A_k
\subseteq
\bigcup_{i=1}^{s}\operatorname{Fr} O_i^1
\]
and
\[
\text{c) }\quad
\operatorname{Int} A_k\cap \operatorname{Int} A_j=\varnothing
\quad (j=1,2,\ldots,k-1).
\]
The partition \(\alpha=\{A_1,A_2,\ldots,A_s\}\) is the desired one. Indeed, \(\alpha\) is inscribed in \(\omega\), and
\[
\operatorname{Ind}\operatorname{Fr}(\operatorname{Int} A_j)
\leq
\operatorname{Ind}\left(\bigcup_{i=1}^{s}\operatorname{Fr} O_i^1\right)
\leq 0,
\]
since \(\operatorname{Ind}\operatorname{Fr} O_i^1\leq 0\).
Proof of Theorem 3. Let \(P=X\times Y\), where \(X,Y\) are bicompacta and \(\operatorname{Ind}X\leq 1,\ \operatorname{Ind}Y\leq 1\). Let a closed set \(F\subset P\) and its neighborhood \(OF\) be arbitrary. One may take a cover
\(\Omega=\{\omega_1\times \omega_2\}\), whose elements are the sets
\(\{O_i\times G_j\}\) \((i=1,2,\ldots,n;\ j=1,2,\ldots,m)\), where
\(\omega_1=\{O_1,\ldots,O_n\}\) is an open cover of the bicompactum \(X\), and
\(\omega_2=\{G_1,\ldots,G_m\}\) is an open cover of the bicompactum \(Y\). In this case \(\Omega\) can be chosen so that the following conditions will be fulfilled:
\[
\text{1) }\quad
\text{if } (O_i\times G_j)\cap F=\varnothing,\ \text{then } [(O_i\times G_j)]\cap F=\varnothing;
\]
\[
\text{2) }\quad
\left[\bigcup_{i=1}^{n}\bigcup_{j=1}^{m}(O_j\times G_j)\right]\subseteq OF,
\quad \text{where } [O_i\times G_j]\cap F\ne\varnothing.
\]
Now, using Lemma 1, construct such partitions
\[
\alpha=\{A_1,A_2,\ldots,A_n\}
\quad\text{and}\quad
\beta_1=\{B_1,B_2,\ldots,B_m\}
\]
of the spaces \(X\) and \(Y\), respectively, that:
a) \(\alpha_1\) is inscribed in \(\omega_1\), \(\beta\) is inscribed in \(\omega_2\);
b) \(\operatorname{Ind}\operatorname{Fr}(\operatorname{Int} A_i)\leq 0\) and
\(\operatorname{Ind}\operatorname{Fr}(\operatorname{Int} B_j)\leq 0\)
\((i=1,2,\ldots,n;\ j=1,2,\ldots,m)\).
The partition
\[
\alpha=\{\alpha_1\times \alpha_2\},
\]
consisting of the sets
\[
A_i\times B_j
\quad (i=1,2,\ldots,n;\ j=1,2,\ldots,m)
\]
of the bicompactum \(P\), has the property that
\[
G=P\setminus \bigcup A_i\times B_j
\]
(where \((A_i\times B_j)\cap F=\varnothing\)) is open in \(P\) and \(G\subseteq OF\). The boundary of \(G\) consists of closed subsets of sets of the form
\[
\operatorname{Fr} A_i\times B_j
\quad\text{and}\quad
A_i\times \operatorname{Fr} B_j
\quad (i=1,2,\ldots,n;\ j=1,2,\ldots,m),
\]
and moreover these sets are such that if two of them intersect, then they intersect in a zero-dimensional closed set. Therefore, from Theorem 2 it follows that
\[
\operatorname{Ind}\operatorname{Fr} G\leq 1.
\]
Theorem 3 is proved.
Remark 1. Note that Lemma 1 is true for any normal space \(X\), provided only that \(\operatorname{Ind}X\leq 1\).
We now introduce two definitions.
Definition 1. We shall say that a closed set \(F\) is normally situated in a normal space \(X\), if for every closed set \(\Phi\subseteq F\) the subspace \(X\setminus \Phi\) is normal.
Example. Let \(S\) be the bicompactum of O. V. Lokutsievskii \((^2)\). In this bicompactum the set \(I\times \omega_1\) has the property that \(S\setminus (I\times \omega_1)\) is normal, but the set \(I\times \omega_1\) does not lie normally in the bicompactum \(S\). If, however, a closed set \(F\subseteq S\) is such that \(F\cap (I\times \omega_1)=\varnothing\), then \(F\) lies normally in \(S\).
Definition 2. A closed set \(F\) will be called normally Ind-lying in a normal space \(X\) if, for every closed set \(\Phi\subseteq F\), the subspace \(X\setminus F\) is normal and
\[
\operatorname{Ind}(X\setminus \Phi)\leq \operatorname{Ind}X.
\]
Theorem 4. If a normal space \(P\) is the sum of two closed subsets \(X\) and \(Y\) in it such that: 1) \(\operatorname{Ind}X\leq n\), \(\operatorname{Ind}Y\leq n\); 2) \(F=X\cap Y\) is a set normally Ind-lying in \(X\) and in \(Y\); 3) \(\operatorname{Ind}F\leq n\), then \(\operatorname{Ind}P\leq n\).
Before proving Theorem 4, we prove Theorem 5, from which Theorem 4 will easily follow.
Theorem 5. Let \(P\) be a normal space. If in \(P\) there exists a closed set \(F\) such that \(\operatorname{Ind}F\leq n\), \(\operatorname{Ind}(P\setminus F)\leq n\), and \(F\) lies normally in \(P\), then \(\operatorname{Ind}P\leq n\).
Proof. We shall prove the theorem by induction on the number \(n\). For the sum of empty sets this is obvious. Suppose that Theorem 5 has already been proved for \(n-1\), i.e. if \(P\) is a normal space and in \(P\) there exists a closed set \(F\), normally lying in \(P\), such that \(\operatorname{Ind}F\leq n-1\) and \(\operatorname{Ind}(P\setminus F)\leq n-1\), then \(\operatorname{Ind}P\leq n-1\). We now prove Theorem 5 for \(n\).
Let \(\Phi\) be closed in \(P\), and let \(O\Phi\) be an arbitrary neighborhood of it.
a) If \(\Phi\cap F=\varnothing\), then there exists a neighborhood \(O_1\Phi\subseteq O\Phi\) such that
\[
\operatorname{Ind}\operatorname{Fr} O_1\Phi\leq n-1.
\]
b) Let \(\Phi\cap F\neq \varnothing\). Denote by \(\Phi_1\) and \(O\Phi_1\) the sets
\[
\Phi_1=\Phi\cap F,\qquad O\Phi_1=O\Phi\cap F.
\]
Since \(\operatorname{Ind}F\leq n\), choose a neighborhood \(O_1\Phi_1\subseteq O\Phi_1\) of the set \(\Phi_1\) such that
\[
\operatorname{Ind}\operatorname{Fr}_{F} O_1\Phi_1\leq n-1.
\]
Put
\[
\Gamma=F\setminus [O_1\Phi_1],\qquad
G_1=P\setminus \operatorname{Fr}_{F}O_1\Phi_1.
\]
Then \(G_1\) is a normal space, \(\Gamma\) and \(O_1\Phi_1\) are closed in \(G_1\), and \(\Gamma\cap O_1\Phi_1=\varnothing\), \(\operatorname{Ind}(P\setminus F)\leq n\). Consider the sets
\[
\Phi_2=\Phi\cup O_1\Phi_1,\qquad
\Phi'_2=\Gamma\cup (G_1\setminus O\Phi).
\]
We shall have \(\Phi_2\cap \Phi'_2=\varnothing\), and \(\Phi_2,\Phi'_2\) are closed in \(G_1\). Now choose open sets \(G_2\) and \(G'_2\) in \(G_1\) such that
\[
\Phi_2\subseteq G_2,\qquad \Phi'_2\subseteq G'_2,\qquad [G_2]_{G_1}\cap [G'_2]_{G_1}=\varnothing.
\]
Next consider the sets
\[
G_3=G_2\setminus F,\qquad G'_3=G'_2\setminus F.
\]
We have
\[
[G_3]_{(P\setminus F)}\cap [G'_3]_{(P\setminus F)}=\varnothing.
\]
Since \(\operatorname{Ind}(P\setminus F)\leq n\), choose an open set \(G_4\) in \(P\setminus F\) such that
\[
[G_3]_{(P\setminus F)}\subseteq G_4,\qquad
[G_4]_{(P\setminus F)}\cap [G'_3]_{(P\setminus F)}=\varnothing
\]
and
\[
\operatorname{Ind}\operatorname{Fr}_{(P\setminus F)}G_4\leq n-1.
\]
The set
\[
G_5=G_4\cup O_1\Phi_1
\]
is open in \(P\) and
\[
\Phi\subseteq G_5\subseteq O\Phi.
\]
Notice that
\[
\operatorname{Fr}_{P}G_5=\operatorname{Fr}_{(P\setminus F)}G_4\cup \operatorname{Fr}_{F}O_1\Phi_1,
\]
where
\[
\operatorname{Ind}\operatorname{Fr}_{F}O_1\Phi_1\leq n-1,
\]
\(\operatorname{Fr}_{F}O_1\Phi_1\) lies normally in \(\operatorname{Fr}_{P}G_5\), and
\[
\operatorname{Ind}\bigl(\operatorname{Fr}_{P}G_5\setminus \operatorname{Fr}_{F}O_1\Phi_1\bigr)
=
\operatorname{Ind}\operatorname{Fr}_{(P\setminus F)}G_4\leq n-1.
\]
Thus, \(\operatorname{Ind}\operatorname{Fr}_{P}G_5\leq n-1\). Theorem 5 is proved.
Remark 2. The bicompactum of Lokutsievskii \((^2)\) \(S\) is represented as the sum of the closed set \(F=I\times \omega_1\) and the normal set \((S\setminus F)\), \(\operatorname{Ind}F\leq 1\), \(\operatorname{Ind}(S\setminus F)\leq 1\), while \(\operatorname{Ind}S=2\). But, as was said in Remark 1, the set \(F\) does not lie normally in \(S\). Thus, the concept of a normally lying set is essential.
We now prove Theorem 4. Let
\[
P=X\cup Y,\qquad F=X\cap Y.
\]
Let a closed set \(\Phi\subseteq P\) and its neighborhood \(O\Phi\) be arbitrary.
a) If \(\Phi\cap F=\varnothing\), then there exists a neighborhood \(O_1\Phi\subseteq O\Phi\) such that
\[
\operatorname{Ind}\operatorname{Fr}O_1\Phi\leq n-1.
\]
b) Let
\[
\Phi\cap F=\Phi_1\neq\varnothing.
\]
Put
\[
O\Phi_1=F\cap O\Phi.
\]
Choose \(O_1\Phi_1\subseteq O\Phi_1\) in such a way that
\[
\operatorname{Ind}\operatorname{Fr}_{F}O_1\Phi_1\leq n-1.
\]
Let
\[
F_1=F\setminus [O_1\Phi_1].
\]
Then \(F_1\) and \(O_1\Phi_1\) are closed in
\[
G=P\setminus \operatorname{Fr}_{F}O_1\Phi_1
\]
and
\[
F_1\cap O_1\Phi_1=\varnothing.
\]
Consider now the sets
\[
\Phi_2=\Phi\cup O_1\Phi_1,\qquad
\Phi'_2=F_2\cup (G\setminus O\Phi).
\]
The sets \(\Phi_2,\Phi'_2\) are closed in \(G\) and
\[
\Phi_2\cap \Phi'_2=\varnothing.
\]
Te-
now take the sets \(X_1=X\cap \Phi_2,\ X_1'=X\cap \Phi_2'\) and \(Y_1=Y\cap \Phi_2,\ Y_1'=Y\cap \Phi_2',\ G_X=X\cap G,\ G_Y=Y\cap G\). We have
\(G_X=X\setminus \operatorname{bd}_F O_1\Phi_1,\ G_Y=Y\setminus \operatorname{bd}_F O_1\Phi_1\); consequently, \(G_X,\ G_Y\) are normal and \(\operatorname{Ind}G_X\le n,\ \operatorname{Ind}G_Y\le n\). Therefore we can take an open subset \(\Gamma_X\) (\(\Gamma_Y\)) in \(G_X\) (\(G_Y\)) such that
\(X_1\subset \Gamma_X\) (\(Y_1\subset \Gamma_Y\)), \([\Gamma_X]\cap X_1'=\varnothing\), \(([\Gamma_Y]\cap Y_1'=\varnothing)\), and
\(\operatorname{Ind}\operatorname{bd}_{G_X}\Gamma_X\le n-1\)
\((\operatorname{Ind}\operatorname{bd}_{G_Y}\Gamma_Y\le n-1)\). The set
\(\Gamma=\Gamma_X\cup \Gamma_Y\) is open in \(G\), and hence open also in \(P\), and
\[
\operatorname{bd}_P\Gamma
=
\operatorname{bd}_{G_X}\Gamma_X
\cup
\operatorname{bd}_{G_Y}\Gamma_Y
\cup
\operatorname{bd}_F O_1\Phi_1,
\]
where
\[
\operatorname{bd}_{G_X}\Gamma_X\cup \operatorname{bd}_{G_Y}\Gamma_Y=\varnothing,
\]
therefore
\[
\operatorname{Ind}(\operatorname{bd}_{G_X}\Gamma_X\cap \operatorname{bd}_{G_Y}\Gamma_Y)\le n-1
\]
and
\[
\operatorname{Ind}\operatorname{bd}_F O_1\Phi_1\le n-1.
\]
Further, we see that \(\operatorname{bd}_F O_1\Phi_1\) lies normally in \(\operatorname{bd}_P\Gamma\) and
\[
\operatorname{bd}_F O_1\Phi_1\cap
(\operatorname{bd}_{G_X}\Gamma_X\cup \operatorname{bd}_{G_Y}\Gamma_Y)
=\varnothing;
\]
consequently, by Theorem 5,
\[
\operatorname{Ind}\operatorname{bd}_P\Gamma\le n-1.
\]
Theorem 4 is proved. From Theorems 4 and 5 it follows that
Theorem \(5'\) (Dowker \((^1)\)). Let \(P\) be a hereditarily normal space. If \(F\subset P\) is closed and \(\operatorname{Ind}F\le n,\ \operatorname{Ind}(P\setminus F)\le n\), then \(\operatorname{Ind}P\le n\).
Theorem \(4'\). Let \(P=X\cup Y\) be a hereditarily normal space; \(X,\ Y\) are closed in \(P\) and \(\operatorname{Ind}(X\cap Y)\le n,\ \operatorname{Ind}(X\setminus F)\le n,\ \operatorname{Ind}(Y\setminus F)\le n\), where \(F=X\cap Y\). Then \(\operatorname{Ind}P\le n\).
In conclusion I express my gratitude to my supervisor V. I. Ponomarev for his attention.
Moscow State University
named after M. V. Lomonosov
Received
7 XII 1966
CITED LITERATURE
\(^{1}\) C. H. Dowker, Quart. J. Math. Oxford, 4, 267 (1953).
\(^{2}\) O. V. Lokutsievskii, DAN, 67, No. 2 (1949).