Abstract Generated abstract
The paper studies the possible arrangements of ovals of nonsingular real plane curves of degree six, especially those with nine to eleven ovals, in relation to earlier constructions of Harnack and Hilbert and restrictions from Petrovskii’s theorem. It states a corrected classification claim: types below a specified boundary in the list of logical possibilities exist, while those above it do not, with complete proofs referred to elsewhere. The main contribution of the note is an explicit construction, using reducible sextics, bifurcation of nodes, and successive quadratic transformations, of a sextic curve of type 5 over 1 with 5 exterior ovals, and consequently of type 5 over 1 with 4 exterior ovals. It also records results on which reducible curves can yield certain sextic types and describes related series of higher degree M-curves.
Full Text
D. A. Gudkov
ON THE ARRANGEMENT OF THE OVALS OF A CURVE OF THE SIXTH ORDER
(Presented by Academician I. G. Petrovskii, 5 VII 1968)
MATHEMATICS
- A nonsingular plane real curve of the 6th order \(C_6\)* can have, by Harnack \((^1)\), at most 11 ovals. We shall say that a curve \(C_6\) has type \(\dfrac{k}{1}\,l\) (or is a \(C_6\)-curve \(\dfrac{k}{1}\,l\)) if it has a certain oval \(\alpha\) (the principal one), inside which there lie \(k\) ovals exterior to one another and \(l\) ovals outside the oval \(\alpha\) and exterior to one another (see \((^{11})\)). The type of a curve \(C_6\) consisting of \(k\) ovals exterior to one another will be denoted by \(k\). A curve \(C_6\) can have the following logically possible types with 11, 10, and 9 ovals:
Table 1
\[ \begin{gathered} \dfrac{10}{1};\quad \dfrac{9}{1}1;\quad \dfrac{8}{1}2;\quad \dfrac{7}{1}3;\quad \dfrac{6}{1}4;\quad \dfrac{5}{1}5;\quad \dfrac{4}{1}6;\quad \dfrac{3}{1}7;\quad \dfrac{2}{1}8;\quad \dfrac{1}{1}9;\quad 11,\\[4pt] \dfrac{9}{1};\quad \dfrac{8}{1}1;\quad \dfrac{7}{1}2;\quad \dfrac{6}{1}3;\quad \dfrac{5}{1}4;\quad \dfrac{4}{1}5;\quad \dfrac{3}{1}6;\quad \dfrac{2}{1}7;\quad \dfrac{1}{1}8;\quad 10,\\[4pt] \dfrac{8}{1},\quad \dfrac{7}{1}1;\quad \dfrac{6}{1}2;\quad \dfrac{5}{1}3;\quad \dfrac{4}{1}4;\quad \dfrac{3}{1}5;\quad \dfrac{2}{1}6;\quad \dfrac{1}{1}7;\quad 9 \end{gathered} \]
A. Harnack constructed a curve \(C_6\) of type \(\dfrac{1}{1}9\) \((^1)\), D. Hilbert one of type \(\dfrac{9}{1}1\) \((^2)\). D. Hilbert, in formulating his 16th problem \((^3)\), expressed the conviction that from the first row of Table 1 there exist only curves of the types \(\dfrac{9}{1}1\) and \(\dfrac{1}{1}9\). H. Kahn \((^4)\) and K. Lebenstein \((^5)\) tried to prove (without success) that a curve \(C_6\) of type 11 does not exist. K. Rohn tried to prove the nonexistence of curves \(C_6\) of types \(\dfrac{10}{1}\) and \(11\) \((^6)\), but there are errors in his work. The nonexistence of a curve \(C_6\) of type 11 follows from the theorem of I. G. Petrovskii \((^9)\). We asserted \((^{11})\) that a curve cannot have the types situated above the broken line in Table 1, and also the types \(\dfrac{5}{1}3\), \(\dfrac{5}{1}4\), and \(\dfrac{5}{1}5\). However, in the proofs (which were not published) of the nonexistence of curves \(C_6\) of types \(\dfrac{5}{1}3\), \(\dfrac{5}{1}4\), \(\dfrac{5}{1}5\), \(\dfrac{6}{1}3\), \(\dfrac{6}{1}4\), we made errors. After correcting the errors and carrying out additional analysis it turned out that curves \(\dfrac{6}{1}3\) and \(\dfrac{6}{1}4\) do not exist, the curve \(\dfrac{5}{1}3\) is constructed by D. Hilbert’s method, and the curves \(\dfrac{5}{1}4\) and \(\dfrac{5}{1}5\) exist, but are not constructed by the methods of A. Harnack and D. Hilbert.
Thus, curves \(C_6\) of the types situated below the broken line in Table 1 exist, while those above the broken line do not exist. (For complete proofs of this assertion see \((^{13})\).)
* By \(C_m\), \(\overline{C}_m\), etc., in this note is denoted a plane real curve of the \(m\)-th order.
- In the present note we shall set forth the idea of constructing a curve of type \(\dfrac{5}{1}\,5\) (and consequently also \(\dfrac{5}{1}\,4\)).
Lemma 1. Let \(F(x)\) be an irreducible real simple (i.e., all its singular points are simple double points) curve of degree 6, let \(y_0, y_1, y_2\) be singular points of the curve \(F\), and let the lines \(x_i \equiv y_k y_l\) \((i,k,l=0,1,2\) and distinct) not be tangent to the curve \(F\). Then, under the quadratic transformation
\[ x_0=y_1y_2,\qquad x_1=y_0y_2,\qquad x_2=y_0y_1 \tag{1} \]
(with fundamental points \(y_0, y_1, y_2\) and fundamental lines \(x_0, x_1, x_2\)), the curve \(F(x)\) is transformed in the plane \((y)\) into a curve \(F_{(1)}(y)\)—an irreducible real simple curve of degree 6, having at the points \(x_0, x_1, x_2\) simple double points. The remaining singular points of the curve \(F(x)\) (except for \(y_0, y_1, y_2\)) are transformed into the same kind of singular points of the curve \(F_{(1)}(y)\), and the transformation (1) establishes a one-to-one and continuous correspondence between the branches of the curves \(F\) and \(F_{(1)}\).
The proof follows easily from the theorems of § 7, Chapter 3 \((^{10})\).
Lemma 2. Let \(F\) be a simple real unicursal curve of degree 6 and let all its (10) singular points be real.
Then, by an arbitrarily small change of the coefficients of the curve \(F\), one can obtain a curve \(\Phi\) of degree 6 isotopic to \(F\), for which the line through any two singular points is not tangent to the curve \(\Phi\).
The proof is not difficult.
Theorem 1. There exists a curve \(C_6\) of type \(\dfrac{5}{1}\,5\).
Proof. Let \(C_3\) be a unicursal curve with a node \(z_1\) (see Fig. 1a). On \(C_3\) there exists a point \(z_2\) such that on the arc \(z_1z_2\) there are no inflection points of the curve \(C_3\). By rotating the line \(z_1z_2\) about the point \(z_2\), we obtain a line \(L_1\), intersecting \(C_3\) further at the points \(z_3\) and \(z_4\) on the loop of the curve \(C_3\). The tangent to \(C_3\) at the point \(z_2\) intersects \(C_3\) further at the point \(Q\). We may assume that \(z_2\) is so close to \(z_1\) that the whole portion of the curve \(C_3\) \(Qz_1z_2\) lies in the finite part of the plane. Next, by rotating the line \(z_1z_2\) about the point \(O\) (lying on the exterior segment \(z_1z_2\)), we obtain a line \(L_2\), intersecting the tangent \(Qz_2\) at a point \(P\), lying on the finite segment \(Qz_2\), and \(C_3\) at the points \(z_6, z_7\) (on the arc \(z_1z_2\)) and \(z_5\). \(L_2\) intersects \(L_1\) at the point \(z_8\). Finally, let us move the tangent \(z_2Q\) into the position \(L_3\) in the following way: move the point of tangency to \(z_9\) (in the direction from \(z_7\) to \(z_2\)), then rotate the tangent to \(C_3\) at \(z_9\) about \(z_9\) so as to obtain a line intersecting \(C_3\) at a point \(z_{10}\), close to \(z_9\) and situated on the other side of \(z_9\) than the point \(z_2\), and also at some point \(z_{11}\) (close to \(Q\)). \(L_3\) intersects the lines \(L_1\) and \(L_2\) at the points \(z_{12}\) and \(z_{13}\). Observe that, under the displacement of \(Qz_2\) into \(L_3\), the point \(P\) passes into \(z_{13}\). This displacement may be assumed so small that the line \(z_2z_{13}\) has with \(C_3\), on the arc \(z_1Oz_{11}\), two points of intersection. The curve \(C_3L_1L_2L_3 \equiv \Phi\) is a simple reducible curve of degree 6 with 13 nodes. By Theorem 10, § 6 \((^{12})\), one can bifurcate the nodes \(z_8, z_4\), and \(z_{10}\) and preserve the remaining nodes of the curve \(\Phi\), so as to obtain a simple unicursal curve \(F\) of Fig. 1b. Choose the fundamental points \(y_0, y_1, y_2\) of the transformation (1) at \(z_2, z_{13}\), and \(z_{12}\). In the plane \((y)\) we obtain (by Lemmas 1 and 2) a curve \(F_{(1)}(y)\) with new nodes \(x_0, x_1, x_2\). The nodes \(z_2, z_{13}\), and \(z_{12}\) disappear, while the remaining nodes of the curve \(F(x)\) are preserved, and we denote them by the former letters. Then subject the curve \(F_{(1)}(y)\) to the transformation (1), choosing as fundamental points \(y_0', y_1', y_2'\) the points \(z_5, z_1\), and \(z_3\). Let \(x_0', x_1', x_2'\) be the corresponding fundamental lines. Then in the plane \((y')\) we obtain a curve \(F_{(2)}(y')\) with simple double points \(x_0', x_1', x_2'; x_0, x_1, x_2; z_6, z_9, z_{11}\). Choose the fundamental points \(y_0'', y_1'', y_2''\) of the transformation (1) of the curve \(F_{(2)}(y')\) at the points \(x_0, z_9, z_{11}\), and denote the fundamental lines by \(x_0'', x_1'', x_2''\). In the plane \((y'')\), we obtain a curve \(F_{(3)}(y'')\) with singular points \(x_0'', x_1'', x_2''; x_0'\),
\(x_1',\ x_2';\ x_1,\ x_2,\ z_6,\ z_7\). Finally, for the curve \(F_{(3)}(y''')\) we choose the fundamental points \(y_0''',\ y_1''',\ y_2'''\) of the transformation (1) at the points \(x_0',\ z_6,\ z_7\), and denote the fundamental lines through them by \(x_0''',\ x_1''',\ x_2'''\). In the plane \((y''')\) we obtain the curve \(F_{(4)}(y''')\)—a simple unicursal curve of the 6th order (Fig. 1в) of type \(\dfrac{5}{1}\,5\). Under the last three quadratic transformations the lines \(x_1', x_2';\ x_0'', x_1'', x_2''\) and \(x_0''', x_1''', x_2'''\) may intersect the corresponding curves \(F_{(1)}, F_{(2)}\), and \(F_{(3)}\) in two real points. Then the corresponding points of the curve in Fig. 1в will be nodes analogous to the nodes \(x_1, x_2\). The curve \(F_{(4)}\) in this case always has type \(\dfrac{5}{1}\,5\). The theorem is proved.
Fig. 1
Theorems 2 and 3 can be proved.
Theorem 2.
\(1^\circ\). A curve \(C_6\) of type \(\dfrac{9}{1}\,1\) can be obtained from a simple reducible curve only of type \(C_2 \cdot C_4\).
\(2^\circ\). A curve \(C_6\) of type \(\dfrac{5}{1}\,5\) can be obtained from a simple reducible curve only of type \(C_1 \cdot C_5\) (Fig. 1a).
\(3^\circ\). A curve \(C_6\) of type \(\dfrac{1}{1}\,9\) can be obtained from simple reducible curves of each of the types \(C_2 \cdot C_4;\ C_1 \cdot C_5;\ C_3 \cdot C_3\).
A. Wiman \((^{7})\) showed that there exist curves of even orders \(m \geqslant 8\) with the greatest number of ovals (\(M\)-curves) which are not constructed by the methods of Harnack and Hilbert (see also \((^{8})\), Chapter 4, § 2).
Theorem 3. From the curve \(C_6 = C_1 \cdot C_5\) of Fig. 1, by applying Harnack’s construction, one obtains a series of \(M\)-curves. In particular, the following curves are obtained:
1) For odd \(m \geqslant 7\), a curve of type
\[
\mathrm{I}\,\frac{5}{1}\left\{\frac{m^2-3m}{2}-5\right\},
\]
i.e., having an odd branch \(\mathrm{I}\), five ovals inside one of them, and \(\frac{m^2-3m}{2}-5\) exterior ovals (outside one another).
2) For even \(m \geqslant 6\), a curve of type
\[
\frac{5}{1}\,\frac{\left\{\frac18 m(m-6)\right\}}{1}
\left\{\frac{3m^2-6m}{8}-4\right\},
\]
which are not constructed by the methods of A. Harnack, D. Hilbert, and A. Wiman \((^{1,2,7})\).
Gorky State University
named after N. I. Lobachevsky
Received
2 VII 1968
CITED LITERATURE
\({}^{1}\) H. Hornack, Math. Ann., 10, 189 (1876).
\({}^{2}\) D. Hilbert, Math. Ann., 38, 115 (1891).
\({}^{3}\) D. Hilbert, Arch. Math. u. Phys., 3 Reihe, 1, 44 (1901).
\({}^{4}\) G. Kahn, Inaugural Dissertation, Göttingen, 43 pp., 1909.
\({}^{5}\) K. Löbenstein, Inaugural Dissertation, Göttingen, 37 pp., 1910.
\({}^{6}\) K. Rohn, Math. Ann., 73, 177 (1913).
\({}^{7}\) A. Wiman, Math. Ann., 90, 222 (1923).
\({}^{8}\) I. L. Coolidge, A Treatise on Algebraic Plane Curves, Oxford, 1931.
\({}^{9}\) I. Petrovsky, Ann. Math., 39, No. 1, 187 (1938).
\({}^{10}\) R. Walker, Algebraic Curves, Moscow, 1952.
\({}^{11}\) D. A. Gudkov, DAN, 48, No. 4, 521 (1954).
\({}^{12}\) D. A. Gudkov, Matem. sborn., 67 (109), 4, 481 (1965).
\({}^{13}\) D. A. Gudkov, Uch. zap. Gorky Univ., issue 87 (1968).