Abstract Generated abstract
The paper studies periodic solutions of the one-dimensional diffusion equation on a finite interval, motivated by self-oscillatory phenomena previously treated mainly for semi-infinite domains. It formulates the bounded-domain problem with a fixed concentration at one endpoint and a nonlinear, possibly S-shaped flux condition at the other, then represents solutions through Fourier series and through Green-function integral formulas. Special attention is given to piecewise constant and more general periodic boundary fluxes, yielding explicit coefficient formulas, monotonicity conditions, and sufficient inequalities for solutions with prescribed phases of increase and decrease. The analysis relates the bounded-domain construction to earlier semi-infinite results, showing that, for sufficiently small dimensionless periods corresponding to large interval length, the finite-domain problem admits corresponding periodic solutions.
Full Text
UDC 532.72
HYDROMECHANICS
N. N. KOCHINA
ON ONE SOLUTION OF THE ONE-DIMENSIONAL DIFFUSION EQUATION IN A BOUNDED DOMAIN
(Presented by Academician L. I. Sedov, May 17, 1968)
A qualitative study of self-oscillations arising under certain conditions in oil production or in some electrolytic systems was given in papers \((^{1-3})\). In papers \((^{3-10})\), periodic solutions of the one-dimensional diffusion equation in a semi-infinite domain of variation of the spatial variable \(x\), connected with this problem, were obtained. Below a periodic solution is found for a certain diffusion problem in a bounded domain.
As is known \((^{11})\), the diffusion equation
\[ \partial c / \partial t = D\,\partial^{2}c / \partial x^{2} \tag{1} \]
has periodic solutions of the form
\[ Ae^{\pm \sqrt{\omega/2D}\,x}\cos\left(\mp \sqrt{\omega/2D}\,x+\omega t\right),\qquad Ae^{\pm \sqrt{\omega/2D}\,x}\sin\left(\mp \sqrt{\omega/2D}\,x+\omega t\right). \tag{2} \]
For the semi-infinite interval \(0<x<\infty\), a periodic solution of equation (1) was obtained in paper \((^{4})\).
Let us now consider the following problem: to find a periodic solution of equation (1) for the finite interval \(0<x<l\), satisfying the boundary condition
\[ c(l,t)=c^{0}. \tag{3} \]
We shall seek the function \(c(x,t)\) in the form
\[ c(x,t)=c_{0}+(c^{0}-c_{0})x/l+u(z,\tau), \tag{4} \]
where \(u(z,\tau)\) is a periodic solution of the equation
\[ \partial u/\partial \tau=\partial^{2}u/\partial z^{2} \qquad (\tau=Dt/l^{2},\ z=x/l-1) \tag{5} \]
with period \(T\), satisfying the conditions
\[ u(0,\tau)=0,\qquad \int_{0}^{T}u(z,\tau)\,d\tau=0. \tag{6} \]
Using formulas (2), (5), and (6), it is easy to verify that the desired solution can be represented in the form
\[ u(z,\tau)=\sum_{k=1}^{\infty}u_{k}(z,\tau),\qquad u_{k}(z,\tau)=A_{k}\{e^{\rho_{k}z}\cos(\omega_{k}\tau+\rho_{k}z)- \tag{7} \]
\[ -e^{-\rho_{k}z}\cos(\omega_{k}\tau-\rho_{k}z)\} +B_{k}\{e^{\rho_{k}z}\sin(\omega_{k}\tau+\rho_{k}z)-e^{-\rho_{k}z}\sin(\omega_{k}\tau-\rho_{k}z)\}, \]
where
\[ \rho_{k}=\sqrt{\pi k/T},\qquad \omega_{k}=2\pi k/T, \tag{8} \]
and \(A_{k}\) and \(B_{k}\) denote constants which must be determined from the boundary condition.
We shall now seek a periodic solution of equation (1) for the finite interval \(0<x<l\) with the boundary condition
\[ \partial c(0,t)/\partial x=\Omega[c(0,t)], \tag{9} \]
where \(\Omega\) is an \(S\)-shaped function \((^{2})\), at \(x=0\), and with condition (3) at \(x=l\).
Using formulas (4) and (5), we reduce this problem to finding a solution of the diffusion equation (5) in the form (7), where the constants \(A_k\) and \(B_k\) are found from the boundary condition
\[ \partial u(-1,\tau)/\partial z = F[u(-1,\tau)] \quad (F(u)=l\Omega(c_0+u)-c^0+c_0). \tag{10} \]
Introducing the notation
\[ \begin{aligned} \alpha_k(z)&=2(A_k\cos \rho_k z\,\operatorname{sh}\rho_k z+B_k\sin \rho_k z\,\operatorname{ch}\rho_k z),\\ \beta_k(z)&=2(-A_k\sin \rho_k z\,\operatorname{ch}\rho_k z+B_k\cos \rho_k z\,\operatorname{sh}\rho_k z), \end{aligned} \tag{11} \]
we write equation (10) in the following form:
\[ \sum_{k=1}^{\infty}\left[\alpha'_k(1)\cos\omega_k\tau+\beta'_k(1)\sin\omega_k\tau\right] = \]
\[ =F\left\{-\sum_{k=1}^{\infty}\left[\alpha_k(1)\cos\omega_k\tau+\beta_k(1)\sin\omega_k\tau\right]\right\}. \tag{12} \]
Equation (12), taking into account the notation (11), gives an infinite system of nonlinear equations for finding the constants \(A_k\) and \(B_k\) \((k=1,2,\ldots)\).
If \(F[u(-1,\tau)]=\chi(\tau)\), where \(\chi(\tau)\) is a known periodic function of \(\tau\) with period \(T\), satisfying, by virtue of (6), the condition
\[ \int_0^T \chi(\tau)\,d\tau=0, \tag{13} \]
then, expanding \(\chi(\tau)\) in a Fourier series, one can find the coefficients \(A_k\) and \(B_k\) from (12) and (11).
Let us consider in more detail the case where \(F(u)\) is a piecewise-constant function
\[ F(u)=Q_1 \quad \text{for } 0<\tau<T_1;\qquad F(u)=Q_2 \quad \text{for } T_1<\tau<T. \tag{14} \]
It follows from (6) that in this case the constants \(Q_1,Q_2,T_1\), and \(T\) must be related by
\[ Q_1T_1+Q_2(T-T_1)=0. \tag{15} \]
Formulas (12), (11), and (13) give the following expressions for the coefficients \(A_k\) and \(B_k\):
\[ A_k=\frac{(Q_1-Q_2)}{\pi k\rho_k}\sin\frac{\pi kT_1}{T} \left[ (\mu_k-\nu_k)\cos\frac{\pi kT_1}{T} -(\mu_k+\nu_k)\sin\frac{\pi kT_1}{T} \right], \]
\[ B_k=\frac{(Q_1-Q_2)}{\pi k\rho_k}\sin\frac{\pi kT_1}{T} \left[ (\mu_k+\nu_k)\cos\frac{\pi kT_1}{T} +(\mu_k-\nu_k)\sin\frac{\pi kT_1}{T} \right], \tag{16} \]
\[ \mu_k=\operatorname{ch}\rho_k\cos\rho_k/(\operatorname{ch}2\rho_k+\cos2\rho_k),\qquad \nu_k=\operatorname{ch}\rho_k\sin\rho_k/(\operatorname{ch}2\rho_k+\cos2\rho_k). \]
We now give the solution of the desired problem in another form. Suppose first that the boundary condition at \(z=-1\) has the form
\[ \partial u(-1,\tau)/\partial z=\chi(\tau), \tag{17} \]
where the periodic function \(\chi(\tau)\), for which equality (13) is satisfied, is known. Consider equation (1). The source function \(G(x,t,\xi,\tau)\) for the interval \((0<x<l)\), satisfying the conditions \(\partial G(0,t,\xi,\tau)/\partial x=G(l,t,\xi,\tau)=0\), has the form \((^{11,3})\):
\[ G(x,t,\xi,\tau)=\frac{1}{2\sqrt{\pi D(t-\tau)}}\sum_{k=-\infty}^{\infty}(-1)^k\times \]
\[ \times\left[ \exp\left(-\frac{(x-\xi-2kl)^2}{4D(t-\tau)}\right) + \exp\left(-\frac{(x+\xi-2kl)^2}{4D(t-\tau)}\right) \right]. \]
It can also be represented in the following way:
\[ G(x,t,\xi,\tau)=\frac{2}{l}\sum_{k=0}^{\infty} \exp\left[-\frac{(2k+1)^2\pi D}{4l^2}(t-\tau)\right]\times \]
\[ \times \cos\frac{(2k+1)\pi\xi}{2l}\cos\frac{(2k+1)\pi x}{2l}. \]
Using the source function, we write the solution of equation (5) for \(x=0\) with boundary conditions (6) and (17)
\[ u(0,\tau)=-\int_{-\infty}^{\tau} K(\tau-\sigma)\chi(\sigma)\,d\sigma \quad \left(K(\sigma)=\left[1+2\sum_{n=1}^{\infty}(-1)^n e^{-n^2\sigma}\right]/\sqrt{\pi\sigma}\right). \tag{18} \]
Let now, analogously to (6),
\[ \chi(\tau)=\psi_i(\tau)\quad \text{for } \alpha_i+kT<\tau<\beta_i+kT \]
\[ (i=1,2;\ k=0,\pm 1,\pm 2,\ldots) \tag{19} \]
\[ \alpha_1=pT/2,\quad \alpha_2=\beta_1=T-pT/2,\quad \beta_2=T+pT/2,\quad 0<p<1. \]
It is easy to see that
\[ u_i(0,\tau)=-\int_{\alpha_i}^{\tau}K(\tau-\sigma)\psi_i(\sigma)\,d\sigma+S_i(\tau) \quad (\alpha_i\leq \tau\leq \beta_i), \tag{20} \]
\[ S_i(\tau)=-\sum_{k=0}^{-\infty} \left\{ \int_{\beta_i-T+kT}^{\alpha_i+kT} K(\tau-\sigma)\varphi_i(\sigma)\,d\sigma + \int_{\alpha_i-T+kT}^{\beta_i-T+kT} K(\tau-\sigma)\psi_i(\sigma)\,d\sigma \right\} \]
\[ (\varphi_1=\psi_2,\ \varphi_2=\psi_1). \]
The uniform convergence of the series \(S_i(\tau)\) follows from the fulfillment of condition (13) and from the fact that \(K(\sigma)\) is a monotonically decreasing function of its argument.
Consider again the case of a piecewise-constant function \(F(u)\) of the form (14). Using the following relation from (18),
\[ f(a,b)=\int_a^b K(y)\,dy = \frac{2}{\sqrt{\pi}} \left\{ \sqrt{b}-\sqrt{a} + 2\sum_{n=1}^{\infty}(-1)^n \left[ n\sqrt{\pi}\left(\Phi\left(\frac{n}{\sqrt{b}}\right)- \Phi\left(\frac{n}{\sqrt{a}}\right)\right) + \sqrt{b}e^{-n^2/b}-\sqrt{a}e^{-n^2/a} \right] \right\} \]
\[ \left(\Phi(z)=\frac{2}{\sqrt{\pi}}\int_0^z e^{-y^2}\,dy\right), \tag{21} \]
we write the solution \(u(0,\tau)\) in the following way:
\[ u_i(0,\tau)=Q_i f(\tau-\alpha_i,0)+S_i(\tau) \quad (\alpha_i\leq \tau\leq \beta_i), \]
\[ S_i(\tau)=\sum_{k=0}^{-\infty} \left\{ q_i f(\tau-\beta_i+T-kT,\ \tau-\alpha_i-kT) + Q_i f(\tau-\alpha_i+T-kT,\right. \]
\[ \left. \tau-\beta_i+T-kT) \right\} \quad (q_1=Q_2,\ q_2=Q_1). \tag{22} \]
Using condition (13), it is easy to see that \(du_1(0,\tau)/d\tau>0\), \(du_2(0,\tau)/d\tau<0\).
Let us return to the more general case, when the periodic function \(\chi(\tau)\), defined by formula (19), is given. From formulas (20) we find
\[ \frac{du_i(0,\tau)}{d\tau} = -\frac{1}{\sqrt{\pi}} \left\{ \frac{\psi_i(\alpha_i)}{\sqrt{\tau-\alpha_i}} + \int_{\alpha_i}^{\tau} \frac{\psi_i'(\sigma)\,d\sigma}{\sqrt{\tau-\sigma}} + \right. \]
\[ \left. + \int_{\alpha_i}^{\tau} \frac{\psi_i(\sigma)}{(\tau-\sigma)^{5/2}} \sum_{n=1}^{\infty} \left[(-1)^n e^{-n^2/(\tau-\sigma)}(2n^2-\tau+\sigma)\right]\,d\sigma \right\} + \frac{dS_i}{d\tau}, \]
\[ \frac{dS_i}{d\tau} = -\sum_{k=0}^{-\infty} \left\{ \int_{\beta_i-T+kT}^{\alpha_i+kT} K'(\tau-\sigma)\varphi_i(\sigma)\,d\sigma + \int_{\alpha_i-T+kT}^{\beta_i-T+kT} K'(\tau-\sigma)\psi_i(\sigma)\,d\sigma \right\} \]
\[ (\alpha_i<\tau<\beta_i). \tag{23} \]
It is easy to see that, by virtue of (13), \(dS_1/d\tau>0\). It can be shown that, if \(\psi_1(\tau)<0,\ \psi_2(\tau)>0,\ (1-p)T<2,\ pT<2\), then, in order for the inequalities \(du_1(0,\tau)/d\tau>0\) \((\alpha_1<\tau<\beta_1)\), \(du_2(0,\tau)/d\tau<0\) \((\alpha_2<\tau<\beta_2)\) to hold, it is sufficient that the relations \((i=1,2)\) hold.
\[ (-1)^i\left[\frac{\psi_i(\alpha_i)}{\sqrt{\tau-\alpha_i}}+\int_{\alpha_i}^{\tau}\frac{\psi'_i(\sigma)\,d\sigma}{\sqrt{\tau-\sigma}}-\int_{\alpha_i}^{\tau}\frac{e^{-1/(\tau-\sigma)}(2-\tau+\sigma)\psi_i(\sigma)\,d\sigma}{(\tau-\sigma)^{5/2}}\right]>0. \tag{24} \]
The function \(F\) entering condition (10) may then be regarded as having the form
\[ F(u,\partial u/\partial \tau)= \begin{cases} F_1(u) & \text{for } \partial u/\partial \tau>0,\quad F_1=\psi_1(\tau),\ u=u_1(0,\tau),\\ F_2(u) & \text{for } \partial u/\partial \tau<0,\quad F_2=\psi_2(\tau),\ u=u_2(0,\tau). \end{cases} \]
As an example, let us consider the case in which the functions \(\psi_i(\tau)\) in formula (19) are prescribed by the dependences
\[ \psi_i(\tau)=e_i+d_i(\beta_i-\tau)^{q_i}+f_i(\tau-\alpha_i)^{1/2};\qquad e_1<0,\ d_1<0,\ f_1>0, \tag{25} \]
\[ \frac{1}{2}<q_i<1;\quad e_2>0,\ d_2>0,\ f_2<0. \]
A periodic solution of equation (1) with conditions (3) and (17), where \(\chi(\tau)\) is given by relations (19) and (25), in the semi-infinite domain \(0<x<\infty\) was found in paper \((^6)\). The solution of the corresponding problem in the bounded domain \(0<z<1\) is given by formulas (20), (19), and (25). Moreover, if we introduce the notation
\[ I_1(x,q)=\int_x^{\infty} e^{-z}z^{1/2-q}\,dz,\qquad I_2(x,q)=\int_x^{\infty} e^{-z}z^{q-1/2}\,dz, \]
\[ I_3(x)=\int_x^{\infty} e^{-z}\sqrt{\frac{z}{x}-1}\,dz,\qquad I_4(x)=\int_x^{\infty}\frac{e^{-z}}{z}\sqrt{\frac{z}{x}-1}\,dz, \tag{26} \]
then inequalities (24), sufficient for having \(du_1(0,\tau)/d\tau>0\), \(du_2(0,\tau)/d\tau<0\), take the form \((p_1=1-p,\ p_2=p)\)
\[ (-1)^i\left[e_i\left(1-2e^{-1/p_iT}\right)-d_i\sqrt{p_iT}\left\{\frac{(p_iT)^{q_i-1/2}}{2q_i-1} +2I_1\left(\frac{1}{p_iT},q_i\right)-\right.\right. \]
\[ \left.\left. -I_2\left(\frac{1}{p_iT},q_i\right)\right\} +f_i\sqrt{p_iT}\left\{\frac{\pi}{2}-2I_3\left(\frac{1}{p_iT}\right)+I_4\left(\frac{1}{p_iT}\right)\right\}\right]>0. \tag{27} \]
From (13) and (25) there also follows a relation among the constants \(e_i,d_i,f_i,q_i,p\) and \(T\), coinciding with equality (4.4) of article \((^6)\):
\[ e_2pT+\frac{d_2}{q_2+1}(pT)^{q_2+1}+\frac{2}{3}f_2(pT)^{3/2} +e_1(1-p)T+\frac{d_1}{q_1+1}[(1-p)T]^{q_1+1} +\frac{2}{3}f_1[(1-p)T]^{3/2}=0. \tag{28} \]
From (26) it follows that \(\lim_{x\to\infty} I_j(x,q_i)=0\) \((j=1,2,3,4)\) and \(\lim_{x\to\infty}[(2q_i-1)x^{q_i-1/2}I_i(x,q_i)]=0\) \((i=1,2)\). Therefore, in the limit as \(T\to0\), inequalities (27) pass into inequalities (4.3) of article \((^6)\).
Thus, if there exists a solution of the problem in the semi-infinite domain, then, at least for sufficiently small values of the period \(T\), there also exists a solution of the corresponding problem in the finite domain. (Indeed, \(T\to0\) \((l\to\infty)\), since from formula (5) it follows that the period \(T\) is related to the actual period \(T_*\) of the self-oscillation by the dependence \(T=DT_*/l^2\).)
Putting in formulas (20) \(\psi_1(\sigma)=F_1[u_1(0,\sigma)]\), \(\psi_2(\sigma)=F_2[u_2(0,\sigma)]\), we obtain a nonlinear integral equation for finding the function \(u(0,\sigma)\) \((\alpha_1\leq\sigma\leq\beta_2)\).
Mathematical Institute named after V. A. Steklov
Academy of Sciences of the USSR
Received
8 V 1968
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