NUCLEON COMPOSITION AND EXCITATION ENERGIES OF FISSIONING NUCLEI UPON IRRADIATION OF TARGETS OF Bi$^{209}$, Pb$^{208}$, AND Au$^{197}$ WITH PHOTONS OF ENERGY $E_{\gamma\max}=1$ GeV
PHYSICS
Submitted 1970-01-01 | SovietRxiv: ru-197001.60076 | Translated from Russian

Abstract Generated abstract

This paper examines the nucleon composition and excitation energies of nuclei undergoing photofission when bismuth-209, lead-208, and gold-197 targets are irradiated with photons of maximum energy 1 GeV. The authors derive fissioning-nucleus parameters from measured fragment kinetic energies and mass and energy distribution variances, using the Seaborg-Viola relation, neutron-emission corrections, energy-balance calculations, and comparison with the Nix-Swiatecki model. The analysis indicates that the principal fissioning nuclei most consistent with the experimental fragment distributions are iridium-193 for gold, thallium-205 for lead, and lead-206 for bismuth, with estimated fragment neutron multiplicities of about 17 to 19 and excitation energies near 165 to 190 MeV.

Full Text

UDC 539.173.3

PHYSICS

Academician of the Academy of Sciences of the Ukrainian SSR A. P. KOMAR, B. A. BOCHAGOV, A. A. KOTOV,
G. G. SEMENCHUK, G. E. SOLYAKIN

NUCLEON COMPOSITION AND EXCITATION ENERGIES OF FISSIONING NUCLEI UPON IRRADIATION OF TARGETS OF Bi$^{209}$, Pb$^{208}$, AND Au$^{197}$ WITH PHOTONS OF ENERGY $E_{\gamma\max}=1$ GeV

In the fission of nuclei by high-energy particles, problems always arise concerning the nucleon composition $A$, $Z$ and the excitation energy $E_{\text{exc}}$. Until now these problems have been solved by considering the processes preceding fission. $A$, $Z$ and $E_{\text{exc}}$ were determined by calculation without invoking experimental data relating to the fission process, although they are connected with the characteristics of the fission fragments. In the present work, to determine $A$, $Z$ and $E_{\text{exc}}$, data on the characteristics of fission products are used, in particular the effect of the decrease in the kinetic energy of fragments when neutrons are emitted from them, and the calculation ($^1$) of the mass and energy distributions of fragments at a specified nuclear temperature. The article uses results pertaining only to the “light target nuclei” Bi$^{209}$ and Au$^{197}$, presented in ($^2$), as well as new data for a target of Pb$^{208}$ and refined data for a target of Au$^{197}$, calibrated against Cf$^{252}$ fragments ($^3$). The restriction to the region of light nuclei is due to the fact that the results of the calculations of Nix and Svyatetskii are valid only for symmetric fission of nuclei lighter than radium. In addition, for these nuclei, according to Pleasonton ($^4$), neutron evaporation before fission is insignificant.

The starting formula for our calculations was the Seaborg–Viola formula ($^5$) for the mean kinetic energy of fragments $E_{\text{k}}^{i}$ before the emission of neutrons from them, established on the basis of numerous experimental data. According to this formula,

$$ E_{\text{k}}^{i}=0.1071z^{2}/A^{1/3}+22.2\ \text{MeV}, \tag{1} $$

where $A$ is the mass number and $Z$ is the charge of the fissioning nucleus.

In the course of fragment separation, their excitation is removed by the emission of neutrons and $\gamma$ quanta. By comparing the experimentally determined value of the kinetic energy of the fragments $E_{\text{k}}^{f}$ after neutron emission with $E_{\text{k}}^{i}$, one can in principle determine the number of these neutrons.

An essential question here is the time of neutron emission from the fragments, their spectrum, and the relation between the mass of the fragments and the number of neutrons emitted by them. Numerous and careful measurements of neutron spectra from fission fragments ($^{6,7}$) make it possible to conclude that: 1) the neutrons are emitted by fully accelerated fragments; 2) in the inertial system of the moving fragment their distribution is isotropic; 3) as regards the connection between the number of neutrons and the mass of the fragment, measurements carried out in ($^8$) on fission of U$^{238}$ by $\alpha$ particles with energy 25.5 MeV lead to a dependence of the form

$$ \nu_{\text{l}}/\nu_{\text{h}}=m_{\text{l}}/m_{\text{h}}, $$

from which it may be concluded that, with increasing energy of the bombarding particles, the excitation energy of the nucleus is distributed among the fragments in proportion to their mass. The authors of ($^9$), on fission of U$^{238}$ by protons with energy 450 MeV, arrive at similar conclusions regarding the character of the distribution of excitation energy among the fragments.

Taking into account the above-mentioned regularities in the emission of neutrons from fragments, the relation between \(E_{\mathrm{k}}^{i}\) and \(E_{\mathrm{k}}^{f}\) has the form

\[ E_{\mathrm{k}}^{f}=E_{\mathrm{k}}^{i}\left(1-\nu_{\mathrm{p}}/A\right)+2\nu_{\mathrm{p}}\bar{\eta}/A, \tag{2} \]

where \(\nu_{\mathrm{p}}\) is the total number of neutrons from both fragments; \(\bar{\eta}\) is the mean kinetic energy of a neutron from the fragments.

The experimental values of the kinetic energies \(E_{\mathrm{k}}^{f}\) for fission fragments arising upon irradiation of targets of \(\mathrm{Bi}^{209}\), \(\mathrm{Pb}^{208}\), and \(\mathrm{Au}^{197}\) by \(\gamma\)-quanta with \(E_{\gamma\max}=1\) GeV are presented in Fig. 1. More detailed information on the mass and energy distributions of the fragments is contained in Ref. \((^2)\). Using the experimental values \(E_{\mathrm{k}}^{f}\), as well as relations (1) and (2), one can obtain the total number of neutrons emitted from the fragments:

\[ \nu_{\mathrm{p}}=A\left(1-E_{\mathrm{k}}^{f}/E_{\mathrm{k}}^{i}\right). \tag{3} \]

The second term on the right-hand side of relation (2) has been omitted because it is small in comparison with the first term.

Knowledge of the total number of neutrons emitted from the fragments makes it possible to determine the excitation energy of each of the fragments. The total excitation energy of the fragments is calculated from the obvious relation

Figure 1: Dependence of the mean total kinetic energies of fragments \(E_{\mathrm{k}}^{f}\) on the mass of the heavy fragment for targets \(\mathrm{Bi}^{209}\) (1), \(\mathrm{Pb}^{208}\) (2), \(\mathrm{Au}^{197}\) (3)

Fig. 1. Dependence of the mean total kinetic energies of fragments \(E_{\mathrm{k}}^{f}\) on the mass of the heavy fragment for targets \(\mathrm{Bi}^{209}\) (1), \(\mathrm{Pb}^{208}\) (2), \(\mathrm{Au}^{197}\) (3)

\[ W=\sum_{j=1}^{\nu_{\mathrm{l}}}\left(B_{j\mathrm{l}}+\bar{\eta}_{j\mathrm{l}}\right) +\sum_{j=1}^{\nu_{\mathrm{t}}}\left(B_{j\mathrm{t}}+\bar{\eta}_{j\mathrm{t}}\right)+W_{\gamma}. \tag{4} \]

Here \(B_j\) is the binding energy of neutrons in the light and heavy fragment, respectively; \(W_{\gamma}\) is the energy carried away from the fragments by \(\gamma\)-quanta (taken to be equal to 8 MeV).

The procedure for determining the excitation energy from the calculated \(\nu_{\mathrm{p}}\) was as follows. The process of neutron evaporation from a fragment was considered in reverse order. It was assumed that, after the emission of all neutrons, an energy \(W_{\gamma}/2=4\) MeV remains in the fragment. Then the excitation energy before the emission of the last neutron, or, what is the same, after the introduction of the first neutron, will be

\[ W_1=B_1+\bar{\eta}_1+W_{\gamma}/2. \]

Similarly,

\[ W_2=W_1+B_2+\bar{\eta}_2 \quad \text{and so on.} \]

Since the kinetic energy of a neutron is determined by the value of the excitation energy before its emission from the fragment \((^{10})\),

\[ \bar{\eta}_j=\frac{4}{3}\left(\frac{8W_j}{A_{\mathrm{frag}}-A_{\mathrm{frag}}+j}\right)^{1/2}, \]

the calculation of \(W\) reduced to solving a system of recurrence equations of the form

\[ W_j=\left(\sqrt{\frac{32}{9\left(A_{\mathrm{frag}}-\nu_{\mathrm{frag}}+j\right)}}+ \sqrt{\frac{32}{9\left(A_{\mathrm{frag}}-\nu_{\mathrm{frag}}+j\right)}+B_j+W_{j-1}}\right)^2 . \tag{5} \]

Table 1

Target Fissioning nucleus $E_k^f$, MeV $\nu_n$ $W$, MeV $\theta$, MeV $\mu_2(E_k^i)$ exp., MeV$^2$ $\mu_2(E)$ theor., MeV$^2$ $\mu_2(M)$ exp., a.m.u.$^2$ $\mu_2(M)$ theor., a.m.u.$^2$
$_{79}\mathrm{Au}^{197}$ $_{77}\mathrm{Ir}^{193}$ $148 \pm 3$ 19 190 2.76 $156 \pm 7$ 178 $365 \pm 8$ 375
$_{82}\mathrm{Pb}^{208}$ $_{81}\mathrm{Tl}^{205}$ $128 \pm 3$ 18 170 2.53 $148 \pm 4$ 159 $280 \pm 6$ 300
$_{83}\mathrm{Bi}^{209}$ $_{82}\mathrm{Pb}^{206}$ $132 \pm 3$ 17 165 2.51 $158 \pm 4$ 159 $272 \pm 5$ 287

The neutron binding energy in the fragment nuclei $B_j$ was taken from Seeger’s mass table (11). The entire problem was solved on a Minsk-22 computer. Then, on the basis of the energy-balance equation, the excitation energy of the fissioning nucleus at the saddle point was determined:

\[ E_{\mathrm{exc}} = E_k^i + W - E_D - B_f . \tag{6} \]

Here $E_D$ is the fission energy, determined from mass tables (11); $B_f$ is the liquid-drop fission barrier (12). The relation between $E_{\mathrm{exc}}$ and the temperature $\theta$ is given, according to (10), in the form

\[ E_{\mathrm{exc}} = \frac{1}{2} A\theta^2 - \theta . \]

Thus, to each possible value

\[ x = \frac{(Z^2/A)}{(Z^2/A)_{\mathrm{cr}}} \]

of the fissioning nuclei it was possible, as a result of the analysis performed, to assign a nuclear temperature $\theta$.

Fig. 2

Fig. 2. Comparison of experimental (points) and calculated (solid lines) dependences of the variances of the energy distributions on the mass of the heavy fragment for the target $\mathrm{Au}^{197}$. 1 — calculation assuming the fissioning nucleus $\mathrm{Au}^{197}$; 2 — $\mathrm{Ir}^{193}$; 3 — $\mathrm{Os}^{192}$.

From these parameters, on the basis of the Nix–Swiȩtecki model (1), the values of the fragment kinetic energies $E_k^i$ and the variances $\mu_2(E_k^i)$ and $\mu_2(M)$ were calculated. The calculated values of the latter quantities were used to construct the dependences of $\mu_2(E_k^i)$ and $\mu_2(M)$ on the mass of the heavy fragment. The constructed curves were compared with the curves obtained experimentally. Since neutron emission from the fragments leads to a distortion of the variances $\mu_2(E_k^f)$, a correction was introduced into them according to the formula from (13):

\[ \mu_2(E_k^i) = \left[ \mu_2(E_k^f) - \frac{4\nu_n \bar{\eta} E_k^i}{4A} \right] \left( 1 - \frac{\nu_n}{A} \right)^{-2}. \]

No correction was introduced into the values of $\mu_2(M)$, since neutron emission at the ratio $\nu_l/\nu_t = m_l/m_t$ does not distort them.

Figure 2 gives the results of a comparison of the experimental and calculated variances of the energy distributions, which are most sensitive to the choice of the parameters of the fissioning nucleus. It is seen that identification of $\mathrm{Ir}^{193}$ as the principal fissioning nucleus in irradiation of a gold target is in the best agreement with the experimental data. The assumption that the initial target nucleus $\mathrm{Au}^{197}$ fissions, or else the nucleus $\mathrm{Os}^{192}$, leads to contradictions with them. Analogous calculations for the $\mathrm{Bi}^{209}$ and $\mathrm{Pb}^{208}$ targets give, respectively, the fissioning nuclei $\mathrm{Pb}^{206}$ and $\mathrm{Tl}^{205}$.

It should be noted that allowance for the experimental errors in the measurement of $E_k^f$ leads to a set of possible fissioning nuclei; however, the nuclei least different from the targets turn out to be those listed in Table 1.

A. F. Ioffe Physico-Technical Institute
Academy of Sciences of the USSR
Leningrad

Received
1 VIII 1969

References

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Submission history

NUCLEON COMPOSITION AND EXCITATION ENERGIES OF FISSIONING NUCLEI UPON IRRADIATION OF TARGETS OF Bi$^{209}$, Pb$^{208}$, AND Au$^{197}$ WITH PHOTONS OF ENERGY $E_{\gamma\max}=1$ GeV